an LR-series circuit has a variable indicator with variable inductance defined by O10 Find the current i (t) if the resistance is 0.2 ohm, the impressed voltage is E (t) = 4, i (0) = 0.
an LR-series circuit has a variable indicator with variable inductance defined by O10 Find the current i (t) if the resistance is 0.2 ohm, the impressed voltage is E (t) = 4, i (0) = 0.
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![In an LR-series circuit, the inductance varies with time according to:
\[
L(t) =
\begin{cases}
1 - \frac{t}{10}, & 0 \leq t < 10 \\
0, & t > 10
\end{cases}
\]
Our objective is to determine the current \( i(t) \), given that the resistance is 0.2 ohms. The impressed voltage is \( E(t) = 4 \) and the initial current \( i(0) = 0 \).
This question sets up an initial-value problem in electrical engineering, where the time-dependent inductance affects the behavior of the circuit's current over time.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F74a43f44-8ce4-41e9-89f6-5a77f02dff59%2F0a68d8eb-24ca-4bd4-bed5-027e7eed5ce2%2Fnfdzrd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In an LR-series circuit, the inductance varies with time according to:
\[
L(t) =
\begin{cases}
1 - \frac{t}{10}, & 0 \leq t < 10 \\
0, & t > 10
\end{cases}
\]
Our objective is to determine the current \( i(t) \), given that the resistance is 0.2 ohms. The impressed voltage is \( E(t) = 4 \) and the initial current \( i(0) = 0 \).
This question sets up an initial-value problem in electrical engineering, where the time-dependent inductance affects the behavior of the circuit's current over time.
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