An jet is flying on a bearing of 38° at 420 miles per hour. Find the component form of the velocity of the Jet. Round your decimal to two places.

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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### Problem Statement: 

An educational question regarding vector components is displayed as follows:

**Question:**
An jet is flying on a bearing of 338° at 420 miles per hour. Find the component form of the velocity of the jet. Round your decimal to two places.

**Solution:**
To solve for the component form of the velocity of the jet, we need to break down the given velocity into its Cartesian components. The bearing of 338° is measured clockwise from the north. 

1. **Convert the Bearing:**
   The bearing of 338° can be converted to standard position angle from the positive x-axis (East):
   - Standard position angle = 450° - bearing = 450° - 338° = 112°.

2. **Velocity Components (Vx and Vy):**
   - Vx = V * cos(112°)
   - Vy = V * sin(112°)

3. **Calculate the Components:**
   Given V = 420 mph:
   - Vx = 420 * cos(112°)
   - Vy = 420 * sin(112°)

4. **Evaluate the Trigonometric Functions:**
   Using trigonometric values:
   - cos(112°) ≈ -0.3746
   - sin(112°) ≈ 0.9272

5. **Final Calculations:**
   - Vx = 420 * (-0.3746) ≈ -157.53 mph
   - Vy = 420 * (0.9272) ≈ 389.42 mph

Thus, the component form of the velocity is approximately:
\[ \mathbf{V} = (-157.53 \, \text{mph}, 389.42 \, \text{mph}) \]

**Answer:**
The component form of the velocity of the jet is approximately \((-157.53, 389.42)\) when rounded to two decimal places.
Transcribed Image Text:### Problem Statement: An educational question regarding vector components is displayed as follows: **Question:** An jet is flying on a bearing of 338° at 420 miles per hour. Find the component form of the velocity of the jet. Round your decimal to two places. **Solution:** To solve for the component form of the velocity of the jet, we need to break down the given velocity into its Cartesian components. The bearing of 338° is measured clockwise from the north. 1. **Convert the Bearing:** The bearing of 338° can be converted to standard position angle from the positive x-axis (East): - Standard position angle = 450° - bearing = 450° - 338° = 112°. 2. **Velocity Components (Vx and Vy):** - Vx = V * cos(112°) - Vy = V * sin(112°) 3. **Calculate the Components:** Given V = 420 mph: - Vx = 420 * cos(112°) - Vy = 420 * sin(112°) 4. **Evaluate the Trigonometric Functions:** Using trigonometric values: - cos(112°) ≈ -0.3746 - sin(112°) ≈ 0.9272 5. **Final Calculations:** - Vx = 420 * (-0.3746) ≈ -157.53 mph - Vy = 420 * (0.9272) ≈ 389.42 mph Thus, the component form of the velocity is approximately: \[ \mathbf{V} = (-157.53 \, \text{mph}, 389.42 \, \text{mph}) \] **Answer:** The component form of the velocity of the jet is approximately \((-157.53, 389.42)\) when rounded to two decimal places.
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