An isotropic point source emits light at wavelength 500 nm with the power of 200 W. a)Suppose that the isotropic light source emits unpolarized light. A linear polarizer is positioned 300 m from the source. Calculate the light intensity immediately after the light passes through the linear polarizer. b)Repeat part (a), but now the isotropic light source emits circularly polarized light. Explain your answer. c)In part (b), after the emitted circularly polarized light passes through the linear polarizer, you have linearly polarized light. How can you convert the linearly polarized light back to a circularly polarized light again? Explain your answer.
An isotropic point source emits light at wavelength 500 nm with the power of 200 W. a)Suppose that the isotropic light source emits unpolarized light. A linear polarizer is positioned 300 m from the source. Calculate the light intensity immediately after the light passes through the linear polarizer. b)Repeat part (a), but now the isotropic light source emits circularly polarized light. Explain your answer. c)In part (b), after the emitted circularly polarized light passes through the linear polarizer, you have linearly polarized light. How can you convert the linearly polarized light back to a circularly polarized light again? Explain your answer.
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An isotropic point source emits light at wavelength 500 nm with the power of 200 W.
a)Suppose that the isotropic light source emits unpolarized light. A linear polarizer is positioned 300 m from the source. Calculate the light intensity immediately after the light passes through the linear polarizer.
b)Repeat part (a), but now the isotropic light source emits circularly polarized light. Explain your answer.
c)In part (b), after the emitted circularly polarized light passes through the linear polarizer, you have linearly polarized light. How can you convert the linearly polarized light back to a circularly polarized light again? Explain your answer.
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