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An iron can weighing 50 grams absorbs 256.0 J of heat and warms by 11.4°C. What is the specific heat of the iron can? (Formula: Q(heat) = mCpAT) %3D O 1.60 J/gC O 0.45 J/gC 5.43J/gC O 0.20J/gC

An iron can weighing 50 grams absorbs 256.0 J of heat and warms by 11.4°C. What is the specific heat of the iron can? (Formula: Q(heat) = mCpAT) %3D O 1.60 J/gC O 0.45 J/gC 5.43J/gC O 0.20J/gC

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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an iron can weighing 50 grams absorbs 256.0 J of heat and warms by 11.4 degrees C. What is the specific heat of the iron can? (Formula: Q(heat)=mCpdetlaT)
E. None of these are cor gct. Clear sele An iron can weighing 50 grams absorbs 256.0 J of heat and warms by 11.4°C. What is the specific heat of the iron can? (Formula: Q(heat) = mCpAT) O 1.60 J/gC 0.45 J/gC 5.43J/gC 0.20J/gC How much energy (in calories and in Joules) will it take to raise the temperature of 75.0 g of water from 20.0 to 55.0 oC? (Specific Heat = 1 cal / (g oC) and 4.184 J/(g oC)) A. 2630 cal and 630J
Transcribed Image Text:E. None of these are cor gct. Clear sele An iron can weighing 50 grams absorbs 256.0 J of heat and warms by 11.4°C. What is the specific heat of the iron can? (Formula: Q(heat) = mCpAT) O 1.60 J/gC 0.45 J/gC 5.43J/gC 0.20J/gC How much energy (in calories and in Joules) will it take to raise the temperature of 75.0 g of water from 20.0 to 55.0 oC? (Specific Heat = 1 cal / (g oC) and 4.184 J/(g oC)) A. 2630 cal and 630J
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