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An investor has $739,000 to invest in bonds. Bond A yields an average of 7% and the bond B yields 8%. The investor requires that at least 4 times as much money be invested in bond A as in bond B. You must invest in these bonds to maximize his return. This can be set up as a linear programming problem. Introduce the decision variables: x = dollars invested in bond A y = dollars invested in bond B Compute z+ y. Round to the nearest cent.

An investor has $739,000 to invest in bonds. Bond A yields an average of 7% and the bond B yields 8%. The investor requires that at least 4 times as much money be invested in bond A as in bond B. You must invest in these bonds to maximize his return. This can be set up as a linear programming problem. Introduce the decision variables: x = dollars invested in bond A y = dollars invested in bond B Compute z+ y. Round to the nearest cent.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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An investor has $739,000 to invest in bonds. Bond A yields an average of 7% and the bond B yields 8%. The investor requires that at least 4 times as much money be invested in bond A as in bond B. You must invest in these bonds to maximize his return. This can be set up as a linear programming problem. Introduce the decision variables: dollars invested in bond A y = dollars invested in bond B Compute a + y. $ Round to the nearest cent.
Transcribed Image Text:An investor has $739,000 to invest in bonds. Bond A yields an average of 7% and the bond B yields 8%. The investor requires that at least 4 times as much money be invested in bond A as in bond B. You must invest in these bonds to maximize his return. This can be set up as a linear programming problem. Introduce the decision variables: dollars invested in bond A y = dollars invested in bond B Compute a + y. $ Round to the nearest cent.
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