An investment appreciates 2% per year. Originally $5000 is invested. What is an equation for the years since the money is invested as a function of the investment's worth? t= log(F/5000)/log(0.02 t = log(F/5000)/log(1.02) t = log(F/5000)/log(0.98) t = log(F/5000)/log(-1.02)
An investment appreciates 2% per year. Originally $5000 is invested. What is an equation for the years since the money is invested as a function of the investment's worth? t= log(F/5000)/log(0.02 t = log(F/5000)/log(1.02) t = log(F/5000)/log(0.98) t = log(F/5000)/log(-1.02)
Chapter6: Exponential And Logarithmic Functions
Section: Chapter Questions
Problem 4PT: An investment account was opened with aninitial deposit of 9,600 and earns 7.4 interest,compounded...
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![An investment appreciates 2% per year. Originally $5000 is invested. What is an
equation for the years since the money is invested as a function of the investment's
worth?
Ot = log(F/5000)/log(0.02
t = log(F/5000)/log(1.02)
Ot = log(F/5000)/log(0.98)
t = log(F/5000)/log(-1.02)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F622dabb2-64a6-4fed-bea4-0a10e8951c98%2Fcc3c5fde-6ef0-4781-9056-0b7b45a25c5d%2Fqr8gzsa_processed.png&w=3840&q=75)
Transcribed Image Text:An investment appreciates 2% per year. Originally $5000 is invested. What is an
equation for the years since the money is invested as a function of the investment's
worth?
Ot = log(F/5000)/log(0.02
t = log(F/5000)/log(1.02)
Ot = log(F/5000)/log(0.98)
t = log(F/5000)/log(-1.02)
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