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An integral balance is appropriate, since we are interested in accumulation after a finite time interval. 8 8 8 my„sys.f f -2700(1-e-0.3 \dt -0 = [ 62000dt – S 57000dt + - e 2700 2700(8) + 0.3(8) 0.3 MT „sys.f -0 = 40000 40000 – 21600 + 816 – 9000 = 26,580 - e %3D The product comes close but doesn't quite achieve the goal of 30,000 immunotoxin molecules accumulated in the cell over 8 h. If you believe that the technology could be improved a bit, though, it looks like a pretty good investment.

An integral balance is appropriate, since we are interested in accumulation after a finite time interval. 8 8 8 my„sys.f f -2700(1-e-0.3 \dt -0 = [ 62000dt – S 57000dt + - e 2700 2700(8) + 0.3(8) 0.3 MT „sys.f -0 = 40000 40000 – 21600 + 816 – 9000 = 26,580 - e %3D The product comes close but doesn't quite achieve the goal of 30,000 immunotoxin molecules accumulated in the cell over 8 h. If you believe that the technology could be improved a bit, though, it looks like a pretty good investment.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Plz help w math integral explain
An integral balance is appropriate, since we are interested in accumulation after a finite time interval. 8 8 8 mT „sys.f -0= [ 62000d – ƒ 57000dt + S -2700(1–e0.3" )dt 2700 e 0.3 -0.3(8) MT „sys.f -0 = 40000 00(8)+ 40000 – 21600 + 816 – 9000 = 26,580 - e = The product comes close but doesn't quite achieve the goal of 30,000 immunotoxin molecules accumulated in the cell over 8 h. If you believe that the technology could be improved a bit, though, it looks like a pretty good investment.
Transcribed Image Text:An integral balance is appropriate, since we are interested in accumulation after a finite time interval. 8 8 8 mT „sys.f -0= [ 62000d – ƒ 57000dt + S -2700(1–e0.3" )dt 2700 e 0.3 -0.3(8) MT „sys.f -0 = 40000 00(8)+ 40000 – 21600 + 816 – 9000 = 26,580 - e = The product comes close but doesn't quite achieve the goal of 30,000 immunotoxin molecules accumulated in the cell over 8 h. If you believe that the technology could be improved a bit, though, it looks like a pretty good investment.
8:40 AM Tue Oct 19 * 16% I +: 0 P3.29 Immunotoxins are molecules designed to specifically kill cancer cells without damaging healthy noncancerous cells. Immunotoxins must accu- mulate inside cancer cells before they can be effective. A start-up biotech company has discovered a new immunotoxin. The company is trying to raise venture capital. You are trying to decide if youlshould invest your millions. The start-up company provides the following data. The immunotoxin enters the typical cancer cell at a rate of 62,000 molecules per hour. Some of the immunotoxin is degraded inside the cancer cell by enzymes. The rate of degradation is estimated to be 2700 (1 e molecules degraded per hour, where t is time in hours since the cancer cell was first exposed to the immunotoxin. The cancer cell also spits out some of the immunotoxin; the rate of immunotoxin leaving the cancer cell is estimated to be 57,000 molecules per hour. You find independent scientific literature that indicates that, for an immunotoxin to successful- ly kill a cancer cell, there must be an accumulation of at least 30,000 munotorin molecules inside the cell after 8 hours. Should you invest? 3.29 Immuno toxin (T) C62,000 Thosr CANCER cell S7 000 Dof Variabies streem Sjotem Constait> 2 (Tin, Taut) 7 (Accum , flow: Comp Total CexNRAte) 20 pert mert Totel こg Dof = 4-4 =0
Transcribed Image Text:8:40 AM Tue Oct 19 * 16% I +: 0 P3.29 Immunotoxins are molecules designed to specifically kill cancer cells without damaging healthy noncancerous cells. Immunotoxins must accu- mulate inside cancer cells before they can be effective. A start-up biotech company has discovered a new immunotoxin. The company is trying to raise venture capital. You are trying to decide if youlshould invest your millions. The start-up company provides the following data. The immunotoxin enters the typical cancer cell at a rate of 62,000 molecules per hour. Some of the immunotoxin is degraded inside the cancer cell by enzymes. The rate of degradation is estimated to be 2700 (1 e molecules degraded per hour, where t is time in hours since the cancer cell was first exposed to the immunotoxin. The cancer cell also spits out some of the immunotoxin; the rate of immunotoxin leaving the cancer cell is estimated to be 57,000 molecules per hour. You find independent scientific literature that indicates that, for an immunotoxin to successful- ly kill a cancer cell, there must be an accumulation of at least 30,000 munotorin molecules inside the cell after 8 hours. Should you invest? 3.29 Immuno toxin (T) C62,000 Thosr CANCER cell S7 000 Dof Variabies streem Sjotem Constait> 2 (Tin, Taut) 7 (Accum , flow: Comp Total CexNRAte) 20 pert mert Totel こg Dof = 4-4 =0
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