An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows: x < 1 1sx < 3 0.30 10.43 3 sx< 4 F(x) = 0.45 4 Sx< 6 0.75 6 S x < 12 12 sx (a) What is the pmf of X? 3 4 6 12 p(x) (b) Using just the cdf, compute P(3 s XS 6) and P(4 s X). P(3 sXS 6) P(4 s X) =

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An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows:
x < 1
1 < x < 3
3 < x < 4
0.30
0.43
F(x) =
4 < x < 6
6 < x < 12
0.45
0.75
1
12 < x
(a) What is the pmf of X?
1
12
p(x)
(b) Using just the cdf, compute P(3 < X < 6) and P(4 < X).
P(3 < X< 6) =
P(4 < X)
Transcribed Image Text:An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows: x < 1 1 < x < 3 3 < x < 4 0.30 0.43 F(x) = 4 < x < 6 6 < x < 12 0.45 0.75 1 12 < x (a) What is the pmf of X? 1 12 p(x) (b) Using just the cdf, compute P(3 < X < 6) and P(4 < X). P(3 < X< 6) = P(4 < X)
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