An insurance company offers its policyholder a number of different premium payment options. For a randomly selected policyholde let X = the number of months between successive payments. The cdf of X is as follows: F(x) = X< 1 0.34 1s x< 3 0.45 3s x< 4 0.49 4 s x< 6 0.84 6 s x< 12 12 < x (a) What is the pmf of X? 1 3 4 6 12 p(x) 1 (b) Using just the cdf, compute P(3 < X< 6) and P(4 < X). P(3 s Xs 6)= P(4 s X) %3D
An insurance company offers its policyholder a number of different premium payment options. For a randomly selected policyholde let X = the number of months between successive payments. The cdf of X is as follows: F(x) = X< 1 0.34 1s x< 3 0.45 3s x< 4 0.49 4 s x< 6 0.84 6 s x< 12 12 < x (a) What is the pmf of X? 1 3 4 6 12 p(x) 1 (b) Using just the cdf, compute P(3 < X< 6) and P(4 < X). P(3 s Xs 6)= P(4 s X) %3D
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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
Transcribed Image Text:An insurance company offers its policyholders
a number of different premium payment
options. For a randomly selected policyholder,
let X= the number of months between
successive payments. The cdf of X is as
follows:
F(x) =
X< 1
0.34 1< x< 3
0.45 3 < x < 4
0.49 4 s x< 6
0.84 6 < x< 12
12 s x
(a) What is the pmf of X?
1 3 4 6 12
p(x)
1
(b) Using just the cdf, compute P(3 < X<6)
and P(4 < X).
P(3 s Xs 6) =
P(4 < X)
%3D
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