An initial population of 8,000 decays for two years until the population is 500. By what percentage per year is the population decaying?

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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An initial population of 8,000 decays for two years until the population is 500.
By what percentage per year is the population decaying?

Expert Solution
Step 1

Given-  An initial population of 8,000 decays for two years until the population is 500.

To find-what percentage per year is the population decaying.

Concept Used- The population decaying can be find out by using the expression,

A=A01-r100nwhere A= intial population, A0= final population and r= rate of deaying.

Step 2

Explanation-As per the question, an initial population of 8,000 decays for two years until the population is 500.

So, substituting the values as A=8,000 , A0=500 and n(number of years)=2 in the expression, A=A01-r100nwe get,

 8000=5001-r10028000500=1-r1002    116=1-r1002

Or, the above expression can be written as,

 1-r100=116 1-r100=±14

Firstly, taking postive sign and solving further, we get,

 

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