An infinitely large horizontal plane carries a uniform surface charge density = -0.368 nC/m². What is the electric field strength in the region above the plane [Select] ? A proton is traveling in this field with initial speed vo = 1.00 × 105 m/s at 0 = 45° angle with respect to the plane, as shown in the figure below Use the coordinate system in the figure and neglect the effect of gravity. How high can the proton go [Select] [Select] ? If the zero potential is at the origin level, i.e., y = 0 level, what is the potential energy and kinetic energy [Select] of the proton when it is at a height of y1 = 0.500 m? What is the proton's kinetic energy at height y2 = 2.00 m [Select]

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An infinitely large horizontal plane carries a uniform surface charge density = -0.368 nC/m². What is the electric
field strength in the region above the plane [Select]
? A proton is traveling in this field with initial
speed vo = 1.00 × 105 m/s at 0 = 45° angle with respect to the plane, as shown in the figure below Use the
coordinate system in the figure and neglect the effect of gravity. How high can the proton go
[Select]
? If the zero potential is at the origin level, i.e., y = 0 level, what is the potential energy
[Select]
and kinetic energy [Select]
of the proton when it is at a height of
31 = 0.500 m? What is the proton's kinetic energy at height y2 = 2.00 m [Select]
y
Vo
Transcribed Image Text:An infinitely large horizontal plane carries a uniform surface charge density = -0.368 nC/m². What is the electric field strength in the region above the plane [Select] ? A proton is traveling in this field with initial speed vo = 1.00 × 105 m/s at 0 = 45° angle with respect to the plane, as shown in the figure below Use the coordinate system in the figure and neglect the effect of gravity. How high can the proton go [Select] ? If the zero potential is at the origin level, i.e., y = 0 level, what is the potential energy [Select] and kinetic energy [Select] of the proton when it is at a height of 31 = 0.500 m? What is the proton's kinetic energy at height y2 = 2.00 m [Select] y Vo
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