An infinite sheet of charge, oriented perpendicular to thex-axis, passes through x = 0. It has area densityon = -2µC/m?. A thick, infinite conducting slab, alsooriented perpendicular to the x-axis, occupies the regionbetween x = a and x = b, where a = 3 cm and b = 4 cm. The conducting slab has anet charge per unit area of o2 = 3 µC/m?. (a) Calculate the net x-component of the electric fieldat the following positions: At x = -1.5 cm: Ex = At x = 1.5 cm: Ex = At x = 3.5 cm: Ex = At x = 8 cm: Ex = (b) Calculate the surface charge densities on the left-hand(oa) and right-hand(n) faces of theconducting slab. You may also find it useful to note therelationship between ơa and Op. Help Enter C/m? C/m? II

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An infinite sheet of charge, oriented perpendicular to thex-axis, passes through x = 0.
It has area densityor = -2µC/m?. A thick, infinite conducting slab, alsooriented
perpendicular to the x-axis, occupies the regionbetween x = a and x = b, where a = 3
cm and b = 4 cm. The conducting slab has anet charge per unit area of oz = 3
µC/m?.
(a) Calculate the net x-component of the electric fieldat the following positions:
At x = -1.5 cm: Ex =
At x = 1.5 cm: Ex =
At x = 3.5 cm: Ex =
At x = 8 cm: Ex =
(b) Calculate the surface charge densities on the left-hand(oa) and right-hand(on)
faces of theconducting slab. You may also find it useful to note therelationship
between oa and on.
Help
Enter
Oa
C/m?
C/m?
Transcribed Image Text:An infinite sheet of charge, oriented perpendicular to thex-axis, passes through x = 0. It has area densityor = -2µC/m?. A thick, infinite conducting slab, alsooriented perpendicular to the x-axis, occupies the regionbetween x = a and x = b, where a = 3 cm and b = 4 cm. The conducting slab has anet charge per unit area of oz = 3 µC/m?. (a) Calculate the net x-component of the electric fieldat the following positions: At x = -1.5 cm: Ex = At x = 1.5 cm: Ex = At x = 3.5 cm: Ex = At x = 8 cm: Ex = (b) Calculate the surface charge densities on the left-hand(oa) and right-hand(on) faces of theconducting slab. You may also find it useful to note therelationship between oa and on. Help Enter Oa C/m? C/m?
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