An infinite sheet charge of has a charge density of +25.9 pC/m-and covers the entire x-y plane. A second infinite sheet of charge ha a charge density of -58.6 pC/m2 covers the entire y-z plane. What is the magnitude of the electric field at any point not on either surface?

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### Electric Field Calculation from Infinite Sheets of Charge

**Problem Statement:**

An infinite sheet of charge has a charge density of +25.9 pC/m² and covers the entire x-y plane. A second infinite sheet of charge has a charge density of -58.6 pC/m² and covers the entire y-z plane.

**Question:**  
What is the magnitude of the electric field at any point not on either surface?

**Instructions:**  
Round your answer to 1 decimal place.

---

When solving this problem, remember that the electric field \( E \) due to an infinite sheet of charge with surface charge density \( \sigma \) is given by:
\[ E = \frac{\sigma}{2 \epsilon_0} \]
where \( \epsilon_0 \) is the permittivity of free space, \( \epsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \).

Since we have two infinite sheets, you need to consider the vector sum of the electric fields produced by each sheet.

1. Calculate \( E_1 \) due to the first sheet:
   \[
   E_1 = \frac{+25.9 \times 10^{-12}}{2 \times 8.85 \times 10^{-12}} \, \text{N/C}
   \]

2. Calculate \( E_2 \) due to the second sheet:
   \[
   E_2 = \frac{-58.6 \times 10^{-12}}{2 \times 8.85 \times 10^{-12}} \, \text{N/C}
   \]

3. Since these fields are perpendicular to each other, use the Pythagorean theorem to find the resultant field \( E \):
   \[
   E = \sqrt{E_1^2 + E_2^2}
   \]

Make sure to round the final answer to one decimal place as instructed.
Transcribed Image Text:### Electric Field Calculation from Infinite Sheets of Charge **Problem Statement:** An infinite sheet of charge has a charge density of +25.9 pC/m² and covers the entire x-y plane. A second infinite sheet of charge has a charge density of -58.6 pC/m² and covers the entire y-z plane. **Question:** What is the magnitude of the electric field at any point not on either surface? **Instructions:** Round your answer to 1 decimal place. --- When solving this problem, remember that the electric field \( E \) due to an infinite sheet of charge with surface charge density \( \sigma \) is given by: \[ E = \frac{\sigma}{2 \epsilon_0} \] where \( \epsilon_0 \) is the permittivity of free space, \( \epsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \). Since we have two infinite sheets, you need to consider the vector sum of the electric fields produced by each sheet. 1. Calculate \( E_1 \) due to the first sheet: \[ E_1 = \frac{+25.9 \times 10^{-12}}{2 \times 8.85 \times 10^{-12}} \, \text{N/C} \] 2. Calculate \( E_2 \) due to the second sheet: \[ E_2 = \frac{-58.6 \times 10^{-12}}{2 \times 8.85 \times 10^{-12}} \, \text{N/C} \] 3. Since these fields are perpendicular to each other, use the Pythagorean theorem to find the resultant field \( E \): \[ E = \sqrt{E_1^2 + E_2^2} \] Make sure to round the final answer to one decimal place as instructed.
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