An infinite sheet charge of has a charge density of +25.9 pC/m-and covers the entire x-y plane. A second infinite sheet of charge ha a charge density of -58.6 pC/m2 covers the entire y-z plane. What is the magnitude of the electric field at any point not on either surface?
An infinite sheet charge of has a charge density of +25.9 pC/m-and covers the entire x-y plane. A second infinite sheet of charge ha a charge density of -58.6 pC/m2 covers the entire y-z plane. What is the magnitude of the electric field at any point not on either surface?
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![### Electric Field Calculation from Infinite Sheets of Charge
**Problem Statement:**
An infinite sheet of charge has a charge density of +25.9 pC/m² and covers the entire x-y plane. A second infinite sheet of charge has a charge density of -58.6 pC/m² and covers the entire y-z plane.
**Question:**
What is the magnitude of the electric field at any point not on either surface?
**Instructions:**
Round your answer to 1 decimal place.
---
When solving this problem, remember that the electric field \( E \) due to an infinite sheet of charge with surface charge density \( \sigma \) is given by:
\[ E = \frac{\sigma}{2 \epsilon_0} \]
where \( \epsilon_0 \) is the permittivity of free space, \( \epsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \).
Since we have two infinite sheets, you need to consider the vector sum of the electric fields produced by each sheet.
1. Calculate \( E_1 \) due to the first sheet:
\[
E_1 = \frac{+25.9 \times 10^{-12}}{2 \times 8.85 \times 10^{-12}} \, \text{N/C}
\]
2. Calculate \( E_2 \) due to the second sheet:
\[
E_2 = \frac{-58.6 \times 10^{-12}}{2 \times 8.85 \times 10^{-12}} \, \text{N/C}
\]
3. Since these fields are perpendicular to each other, use the Pythagorean theorem to find the resultant field \( E \):
\[
E = \sqrt{E_1^2 + E_2^2}
\]
Make sure to round the final answer to one decimal place as instructed.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff3b22dc5-b81c-452b-a8fe-ec73685697af%2Fc6404ebb-5ecc-4c88-9b0b-7d39320cfdee%2Fjvara0k.jpeg&w=3840&q=75)
Transcribed Image Text:### Electric Field Calculation from Infinite Sheets of Charge
**Problem Statement:**
An infinite sheet of charge has a charge density of +25.9 pC/m² and covers the entire x-y plane. A second infinite sheet of charge has a charge density of -58.6 pC/m² and covers the entire y-z plane.
**Question:**
What is the magnitude of the electric field at any point not on either surface?
**Instructions:**
Round your answer to 1 decimal place.
---
When solving this problem, remember that the electric field \( E \) due to an infinite sheet of charge with surface charge density \( \sigma \) is given by:
\[ E = \frac{\sigma}{2 \epsilon_0} \]
where \( \epsilon_0 \) is the permittivity of free space, \( \epsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \).
Since we have two infinite sheets, you need to consider the vector sum of the electric fields produced by each sheet.
1. Calculate \( E_1 \) due to the first sheet:
\[
E_1 = \frac{+25.9 \times 10^{-12}}{2 \times 8.85 \times 10^{-12}} \, \text{N/C}
\]
2. Calculate \( E_2 \) due to the second sheet:
\[
E_2 = \frac{-58.6 \times 10^{-12}}{2 \times 8.85 \times 10^{-12}} \, \text{N/C}
\]
3. Since these fields are perpendicular to each other, use the Pythagorean theorem to find the resultant field \( E \):
\[
E = \sqrt{E_1^2 + E_2^2}
\]
Make sure to round the final answer to one decimal place as instructed.
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