An industrial bandsaw of total length L = 11 m and width w = 0.218 m is tightened between two wheels, each of diameter D = 1.6 m. The total force between the wheels F = 50 kN. For saw-blade steel, E = 200 GPa, v = 0.3. What thickness would you choose to minimize the tensile stress within the saw-blade? Top Wheel d Bottom Wheel Ⓒ00 by MECH 2 UBC
An industrial bandsaw of total length L = 11 m and width w = 0.218 m is tightened between two wheels, each of diameter D = 1.6 m. The total force between the wheels F = 50 kN. For saw-blade steel, E = 200 GPa, v = 0.3. What thickness would you choose to minimize the tensile stress within the saw-blade? Top Wheel d Bottom Wheel Ⓒ00 by MECH 2 UBC
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:An industrial bandsaw of total length L = 11 m and width w = 0.218 m is tightened between two wheels, each of diameter
D = 1.6 m. The total force between the wheels F = 50 kN. For saw-blade steel, E = 200 GPa, v = 0.3. What thickness
would you choose to minimize the tensile stress within the saw-blade?
Top
Wheel
g
Bottom
Wheel
Ⓒ00
by MECH 2 UBC
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