An inductor with inductance L = 0.400 H and negligible resistance is connected to a battery, a switch S, and two resistors, R1 = 11.0 2 and R2 = 15.0 2 (Figure 1). The battery has emf 96.0 V and negligible internal resistance. S is closed at t = 0. Part H When iz has half of its final value, what is i2? Express your answer with the appropriate units. iz = 8.73 A Part I Figure < 1 of 1> When iz has half of its final value, what is i,? Express your answer with the appropriate units. HA S R2 i = Value A 0000

Introductory Circuit Analysis (13th Edition)
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I only need part I, thank you

### Educational Content: Analysis of an Inductive Circuit

#### Circuit Description
An inductor with an inductance \( L = 0.400 \, \text{H} \) and negligible resistance is connected to a battery, a switch \( S \), and two resistors, \( R_1 = 11.0 \, \Omega \) and \( R_2 = 15.0 \, \Omega \). The circuit is depicted in Figure 1. 

The battery has an electromotive force (emf) of \( 96.0 \, \text{V} \) and negligible internal resistance. The switch \( S \) is closed at \( t = 0 \).

#### Circuit Diagram (Figure 1)

- The circuit consists of a battery \( \mathcal{E} \) connected in series with a switch \( S \) and an inductor \( L \). 
- There are two resistors: \( R_1 \) is placed in parallel with \( R_2 \). 
- The currents are denoted by:
  - \( i_1 \) flowing from the battery.
  - \( i_2 \) flowing through \( R_1 \).
  - \( i_3 \) flowing through \( R_2 \) and the inductor \( L \).

#### Problem Analysis

- **Part H:**
  - Question: When \( i_3 \) has half of its final value, what is the current \( i_2 \)?
  - Given Answer: \( i_2 = 8.73 \, \text{A} \).

- **Part I:**
  - Question: When \( i_3 \) has half of its final value, what is the current \( i_1 \)?
  - The answer needs to be expressed with the appropriate units in the provided input field.

This problem involves analyzing the transient response of an R-L circuit when a switch is closed, causing currents through different branches to change over time until they reach a steady state. Understanding the behavior of such circuits is crucial for applications in electrical engineering and physics.
Transcribed Image Text:### Educational Content: Analysis of an Inductive Circuit #### Circuit Description An inductor with an inductance \( L = 0.400 \, \text{H} \) and negligible resistance is connected to a battery, a switch \( S \), and two resistors, \( R_1 = 11.0 \, \Omega \) and \( R_2 = 15.0 \, \Omega \). The circuit is depicted in Figure 1. The battery has an electromotive force (emf) of \( 96.0 \, \text{V} \) and negligible internal resistance. The switch \( S \) is closed at \( t = 0 \). #### Circuit Diagram (Figure 1) - The circuit consists of a battery \( \mathcal{E} \) connected in series with a switch \( S \) and an inductor \( L \). - There are two resistors: \( R_1 \) is placed in parallel with \( R_2 \). - The currents are denoted by: - \( i_1 \) flowing from the battery. - \( i_2 \) flowing through \( R_1 \). - \( i_3 \) flowing through \( R_2 \) and the inductor \( L \). #### Problem Analysis - **Part H:** - Question: When \( i_3 \) has half of its final value, what is the current \( i_2 \)? - Given Answer: \( i_2 = 8.73 \, \text{A} \). - **Part I:** - Question: When \( i_3 \) has half of its final value, what is the current \( i_1 \)? - The answer needs to be expressed with the appropriate units in the provided input field. This problem involves analyzing the transient response of an R-L circuit when a switch is closed, causing currents through different branches to change over time until they reach a steady state. Understanding the behavior of such circuits is crucial for applications in electrical engineering and physics.
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