An inductor with inductance L = 0.400 H and negligible resistance is connected to a battery, a switch S, and two resistors, R1 = 11.0 2 and R2 = 15.0 2 (Figure 1). The battery has emf 96.0 V and negligible internal resistance. S is closed at t = 0. Part H When iz has half of its final value, what is i2? Express your answer with the appropriate units. iz = 8.73 A Part I Figure < 1 of 1> When iz has half of its final value, what is i,? Express your answer with the appropriate units. HA S R2 i = Value A 0000
An inductor with inductance L = 0.400 H and negligible resistance is connected to a battery, a switch S, and two resistors, R1 = 11.0 2 and R2 = 15.0 2 (Figure 1). The battery has emf 96.0 V and negligible internal resistance. S is closed at t = 0. Part H When iz has half of its final value, what is i2? Express your answer with the appropriate units. iz = 8.73 A Part I Figure < 1 of 1> When iz has half of its final value, what is i,? Express your answer with the appropriate units. HA S R2 i = Value A 0000
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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I only need part I, thank you

Transcribed Image Text:### Educational Content: Analysis of an Inductive Circuit
#### Circuit Description
An inductor with an inductance \( L = 0.400 \, \text{H} \) and negligible resistance is connected to a battery, a switch \( S \), and two resistors, \( R_1 = 11.0 \, \Omega \) and \( R_2 = 15.0 \, \Omega \). The circuit is depicted in Figure 1.
The battery has an electromotive force (emf) of \( 96.0 \, \text{V} \) and negligible internal resistance. The switch \( S \) is closed at \( t = 0 \).
#### Circuit Diagram (Figure 1)
- The circuit consists of a battery \( \mathcal{E} \) connected in series with a switch \( S \) and an inductor \( L \).
- There are two resistors: \( R_1 \) is placed in parallel with \( R_2 \).
- The currents are denoted by:
- \( i_1 \) flowing from the battery.
- \( i_2 \) flowing through \( R_1 \).
- \( i_3 \) flowing through \( R_2 \) and the inductor \( L \).
#### Problem Analysis
- **Part H:**
- Question: When \( i_3 \) has half of its final value, what is the current \( i_2 \)?
- Given Answer: \( i_2 = 8.73 \, \text{A} \).
- **Part I:**
- Question: When \( i_3 \) has half of its final value, what is the current \( i_1 \)?
- The answer needs to be expressed with the appropriate units in the provided input field.
This problem involves analyzing the transient response of an R-L circuit when a switch is closed, causing currents through different branches to change over time until they reach a steady state. Understanding the behavior of such circuits is crucial for applications in electrical engineering and physics.
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