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An inductor with an inductance of 57.0 mH and a resistance of 15.0N is connected to the terminals of a battery with an emf of 8.00 V with negligible internal resistance. (i) Find the initial rate of increase of the current in the circuit. (ii) Find the initial rate of increase if current at the instant when the current is 0.500 A. Hint: Use the Kirchoff's rules to the circuit. i = %(1 – e(R/L)t) O a. (i) 140.35 A/s (ii) 8.77 A/s O b. (i) 100.46 A/s (ii) 7.63 A/s O . (1) 176.87 A/s (ii) 10.62 A/s O d. (1) 98.78 A/s (ii) 6.34 A/s O e. (i) 150.33 A/s (ii) 6.87 A/s

An inductor with an inductance of 57.0 mH and a resistance of 15.0N is connected to the terminals of a battery with an emf of 8.00 V with negligible internal resistance. (i) Find the initial rate of increase of the current in the circuit. (ii) Find the initial rate of increase if current at the instant when the current is 0.500 A. Hint: Use the Kirchoff's rules to the circuit. i = %(1 – e(R/L)t) O a. (i) 140.35 A/s (ii) 8.77 A/s O b. (i) 100.46 A/s (ii) 7.63 A/s O . (1) 176.87 A/s (ii) 10.62 A/s O d. (1) 98.78 A/s (ii) 6.34 A/s O e. (i) 150.33 A/s (ii) 6.87 A/s

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An inductor with an inductance of 57.0 mH and a resistance of 15.0 N is connected to the terminals of a battery with an emf of 8.00 V with negligible internal resistance. (i) Find the initial rate of increase of the current in the circuit. (ii) Find the initial rate of increase if current at the instant when the current is 0.500 A. Hint: Use the Kirchoff's rules to the circuit. i = (1 – e(R/L)t) О a. (i) 140.35 A/s (ii) 8.77 A/s O b. (i) 100.46 A/s (ii) 7.63 A/s O . (i) 176.87 A/s (ii) 10.62 A/s O d. (i) 98.78 A/s (ii) 6.34 А/s O e. (i) 150.33 A/s (ii) 6.87 A/s
Transcribed Image Text:An inductor with an inductance of 57.0 mH and a resistance of 15.0 N is connected to the terminals of a battery with an emf of 8.00 V with negligible internal resistance. (i) Find the initial rate of increase of the current in the circuit. (ii) Find the initial rate of increase if current at the instant when the current is 0.500 A. Hint: Use the Kirchoff's rules to the circuit. i = (1 – e(R/L)t) О a. (i) 140.35 A/s (ii) 8.77 A/s O b. (i) 100.46 A/s (ii) 7.63 A/s O . (i) 176.87 A/s (ii) 10.62 A/s O d. (i) 98.78 A/s (ii) 6.34 А/s O e. (i) 150.33 A/s (ii) 6.87 A/s
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