Homework Help is Here – Start Your Trial Now!
Science
Biology
an individual, produced 25-offspring with his normal-eyed wife. Of their children, 14 were heterochromatic and 11 were-normal. Calculate the chi-square value for this observation. x² = Identify the statement that best interprets the results of the chi-square analysis. Refer to the chi-square distribution table to identify the statement that best interprets the chi-square results. t is not unusal that a heterozygous man produced 14 out of 25 offspring wi heterochromia. The total number of normal offspring is significantly lower than expected. It is unusual that a man with heterochromia had 14 out of 25 offspring with heterochromia. There is a significant difference between the observed number of offspring with heterochromia and the number of offspring that were expected to have heterochromia.

an individual, produced 25-offspring with his normal-eyed wife. Of their children, 14 were heterochromatic and 11 were-normal. Calculate the chi-square value for this observation. x² = Identify the statement that best interprets the results of the chi-square analysis. Refer to the chi-square distribution table to identify the statement that best interprets the chi-square results. t is not unusal that a heterozygous man produced 14 out of 25 offspring wi heterochromia. The total number of normal offspring is significantly lower than expected. It is unusual that a man with heterochromia had 14 out of 25 offspring with heterochromia. There is a significant difference between the observed number of offspring with heterochromia and the number of offspring that were expected to have heterochromia.

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
See similar textbooks
icon
Related questions
Question
Suppose a man is heterozygous for heterochromia, an autosomal dominant disorder which causes two different-colored eyes in an individual, produced 25-offspring with his normal-eyed wife. Of their children, 14 were heterochromatic and 11 were-normal. Calculate the chi-square value for this observation. x² = Identify the statement that best interprets the results of the chi-square analysis. Refer to the chi-square distribution table to identify the statement that best interprets the chi-square results. It is not unusal that a heterozygous man produced 14 out of 25 offspring with heterochromia. The total number of normal offspring is significantly lower than expected. It is unusual that a man with heterochromia had 14 out of 25 offspring with heterochromia. There is a significant difference between the observed number of offspring with heterochromia and the number of offspring that were expected to have heterochromia.
Transcribed Image Text:Suppose a man is heterozygous for heterochromia, an autosomal dominant disorder which causes two different-colored eyes in an individual, produced 25-offspring with his normal-eyed wife. Of their children, 14 were heterochromatic and 11 were-normal. Calculate the chi-square value for this observation. x² = Identify the statement that best interprets the results of the chi-square analysis. Refer to the chi-square distribution table to identify the statement that best interprets the chi-square results. It is not unusal that a heterozygous man produced 14 out of 25 offspring with heterochromia. The total number of normal offspring is significantly lower than expected. It is unusual that a man with heterochromia had 14 out of 25 offspring with heterochromia. There is a significant difference between the observed number of offspring with heterochromia and the number of offspring that were expected to have heterochromia.
Chi-square critical values table The chi-square (x²) distribution is often used in hypothesis testing to determine whether the deviation between observed and expected values is due to chance or may be statistically significant. The x² statistic is calculated using the equation x² = ((O-E)²/E) where O represents an observed value and E represents an expected value for an observation category. The summation sign Σ indicates that the quotient (O-E)2/E is calculated for each category and summed over all the categories. The p value is the probability that the difference between two sets of values is due to chance. The x² value and the following table are used to determine the range in which the p value falls. In most scientific disciplines, a p value of 0.05 is chosen as the threshold for statistical significance. The degrees of freedom (df) is generally the number of categories compared minus one. Critical values of the x² distribution p value df 0.950 0.900 0.750 0.500 0.025 0.010 0.005 0.050 3.841 1 5.024 6.635 7.879 2 5.991 7.378 9.210 10.597 3 6.251 7.815 9.348 11.345 12.838 0.250 0.100 0.004 0.016 0.102 0.455 1.323 2.706 0.103 0.211 0.575 1.386 2.773 4.605 0.352 0.584 1.213 2.366 4.108 4 0.711 1.064 1.923 3.357 5.385 7.779 9.488 11.143 13.277 14.860 5 1.145 1.610 2.675 4.351 6.626 9.236 11.070 12.833 15.086 16.750 6 1.635 2.204 3.455 5.348 7.841 10.645 12.592 14.449 16.812 18.548 7 2.167 2.833 4.255 6.346 9.037 12.017 14.067 16.013 18.475 20.278 2.733 3.490 5.071 7.344 10.219 13.362 15.507 17.535 20.090 21.955 3.325 4.168 5.899 8.343 11.389 14.684 16.919 19.023 21.666 23.589 10 3.940 4.865 6.737 9.342 12.549 15.987 18.307 20.483 23.209 25.188 11 4.575 5.578 7.584 10.341 13.701 17.275 19.675 21.920 24.725 26.757 12 5.226 6.304 8.438 11.340 14.845 18.549 21.026 23.337 26.217 28.300 13 5.892 042 9.299 12.340 15.984 19.812 22.362 24.736 27.688 29.819 14 6.571 7.790 10.165 13.339 17.117 21.064 23.685 26.119 29.141 31.319 15 7.261 8.547 11.037 14.339 18.245 22.307 24.996 27.488 30.578 32.801 20 10.851 12.443 15.452 19.337 23.828 28.412 31.410 34.170 37.566 39.997 50 34.764 37.689 42.942 49.335 56.334 63.167 67.505 71.420 76.154 79.490 100 77.929 82.358 90.133 99.334 109.141 118.498 124.342 129.561 135.807 140.169 89
Transcribed Image Text:Chi-square critical values table The chi-square (x²) distribution is often used in hypothesis testing to determine whether the deviation between observed and expected values is due to chance or may be statistically significant. The x² statistic is calculated using the equation x² = ((O-E)²/E) where O represents an observed value and E represents an expected value for an observation category. The summation sign Σ indicates that the quotient (O-E)2/E is calculated for each category and summed over all the categories. The p value is the probability that the difference between two sets of values is due to chance. The x² value and the following table are used to determine the range in which the p value falls. In most scientific disciplines, a p value of 0.05 is chosen as the threshold for statistical significance. The degrees of freedom (df) is generally the number of categories compared minus one. Critical values of the x² distribution p value df 0.950 0.900 0.750 0.500 0.025 0.010 0.005 0.050 3.841 1 5.024 6.635 7.879 2 5.991 7.378 9.210 10.597 3 6.251 7.815 9.348 11.345 12.838 0.250 0.100 0.004 0.016 0.102 0.455 1.323 2.706 0.103 0.211 0.575 1.386 2.773 4.605 0.352 0.584 1.213 2.366 4.108 4 0.711 1.064 1.923 3.357 5.385 7.779 9.488 11.143 13.277 14.860 5 1.145 1.610 2.675 4.351 6.626 9.236 11.070 12.833 15.086 16.750 6 1.635 2.204 3.455 5.348 7.841 10.645 12.592 14.449 16.812 18.548 7 2.167 2.833 4.255 6.346 9.037 12.017 14.067 16.013 18.475 20.278 2.733 3.490 5.071 7.344 10.219 13.362 15.507 17.535 20.090 21.955 3.325 4.168 5.899 8.343 11.389 14.684 16.919 19.023 21.666 23.589 10 3.940 4.865 6.737 9.342 12.549 15.987 18.307 20.483 23.209 25.188 11 4.575 5.578 7.584 10.341 13.701 17.275 19.675 21.920 24.725 26.757 12 5.226 6.304 8.438 11.340 14.845 18.549 21.026 23.337 26.217 28.300 13 5.892 042 9.299 12.340 15.984 19.812 22.362 24.736 27.688 29.819 14 6.571 7.790 10.165 13.339 17.117 21.064 23.685 26.119 29.141 31.319 15 7.261 8.547 11.037 14.339 18.245 22.307 24.996 27.488 30.578 32.801 20 10.851 12.443 15.452 19.337 23.828 28.412 31.410 34.170 37.566 39.997 50 34.764 37.689 42.942 49.335 56.334 63.167 67.505 71.420 76.154 79.490 100 77.929 82.358 90.133 99.334 109.141 118.498 124.342 129.561 135.807 140.169 89
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Genetic variation
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:
9780134580999
Author:
Elaine N. Marieb, Katja N. Hoehn
Publisher:
PEARSON
Biology 2e
Biology 2e
Biology
ISBN:
9781947172517
Author:
Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:
OpenStax
Anatomy & Physiology
Anatomy & Physiology
Biology
ISBN:
9781259398629
Author:
McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:
Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:
9780815344322
Author:
Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:
W. W. Norton & Company
Laboratory Manual For Human Anatomy & Physiology
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:
9781260159363
Author:
Martin, Terry R., Prentice-craver, Cynthia
Publisher:
McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)
Inquiry Into Life (16th Edition)
Biology
ISBN:
9781260231700
Author:
Sylvia S. Mader, Michael Windelspecht
Publisher:
McGraw Hill Education
SEE MORE TEXTBOOKS