An incompressible liquid (specific gravity = 0.7) is being transported along a horizontal, galvanized iron cylindrical pipe (actual inside diameter = 7.5 cm). At a volumetric flow rate of 4.5 L/s, two pressure gauges that are located 100 m apart along the length of the pipe indicate a pressure differential of 12.1 kPa.

Introduction to Chemical Engineering Thermodynamics
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Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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QUESTION 6
Constant cliameter →
assume turbulent &₁ = 0x₂ = 1
√₁₂ = V₁₂
Z₁ = Z₂
An incompressible liquid (specific gravity = 0.7) is being transported along a horizontal, galvanized iron
cylindrical pipe (actual inside diameter = 7.5 cm). At a volumetric flow rate of 4.5 L/s, two pressure gauges
that are located 100 m apart along the length of the pipe indicate a pressure differential of 12.1 kPa.
a) Write the simplified form of the Bernoulli equation that describes the liquid transport between the two
pressure gauges - note that there are no 'minor losses' between the two pressure gauges.
+gz₂+he
P₁ + Qx₁
P
ay
2
+
= hl
gz,
=
P₂
Р
+x
P₁-P₂
for ²
)
Р
A) Assuming that the flow is fully turbulent, solve for the corresponding friction factor.
E =
0.00015m
0.075m
= 0.002
2,
P₁ = P₂ = h₁ p ^ =
)
f=0.023 (from Moody
chart)
2
c) Determine the viscosity (in Pa-s) of the liquid.
f
= AP-2D
PLv2
= 12100 (2) (0.075)
700 (100) (1.0185) 2
= 0.0249 ~ 0.025
ΔΡ
d) Given that the fluid temperature is 20 °C, exactly what fluid do you propose is being transported
through the pipe?
uto
JID
SIN
A
Transcribed Image Text:QUESTION 6 Constant cliameter → assume turbulent &₁ = 0x₂ = 1 √₁₂ = V₁₂ Z₁ = Z₂ An incompressible liquid (specific gravity = 0.7) is being transported along a horizontal, galvanized iron cylindrical pipe (actual inside diameter = 7.5 cm). At a volumetric flow rate of 4.5 L/s, two pressure gauges that are located 100 m apart along the length of the pipe indicate a pressure differential of 12.1 kPa. a) Write the simplified form of the Bernoulli equation that describes the liquid transport between the two pressure gauges - note that there are no 'minor losses' between the two pressure gauges. +gz₂+he P₁ + Qx₁ P ay 2 + = hl gz, = P₂ Р +x P₁-P₂ for ² ) Р A) Assuming that the flow is fully turbulent, solve for the corresponding friction factor. E = 0.00015m 0.075m = 0.002 2, P₁ = P₂ = h₁ p ^ = ) f=0.023 (from Moody chart) 2 c) Determine the viscosity (in Pa-s) of the liquid. f = AP-2D PLv2 = 12100 (2) (0.075) 700 (100) (1.0185) 2 = 0.0249 ~ 0.025 ΔΡ d) Given that the fluid temperature is 20 °C, exactly what fluid do you propose is being transported through the pipe? uto JID SIN A
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