An incandescent light bulb is an inexpensive but highly inefficient device that converts electrical energy into light. It converts about 10 percent of the electrical energy it consumes into light while converting the remaining 90 percent into heat. (A fluorescent light bulb will give the same amount of light while consuming only one-fourth of the electrical energy, and it will last 10 times longer than an incandescent light bulb.) The glass bulb of the lamp heats up very quickly as a result of absorbing all that heat and dissipating it to the surroundings by convection and radiation. Consider a 0.525-m-diameter 100-W light bulb cooled by a fan that blows air at 30°C to the bulb at a velocity of 306 m/s. The surrounding surfaces are also at 30°C, and the emissivity of the glass is 0.9. Assuming 10 percent of the energy passes through the glass bulb as light with negligible absorption and the rest of the energy is absorbed and dissipated by the bulb itself, determine the equilibrium temperature of the glass bulb. Assume a surface temperature of 100°C for evaluation of µs- The properties of air at 1 atm pressure and the free stream temperature of 30°C are k = 0.02588 W/m°C, v = 1.608x1o-5 m²/s, µoo = 1.872x10-5 kg/m.s, Hs at 100°C = 2.181x10-5 kg/m.s, and Pr = 0.7282. 100 W 3 = 0.9* Light, 10 W
An incandescent light bulb is an inexpensive but highly inefficient device that converts electrical energy into light. It converts about 10 percent of the electrical energy it consumes into light while converting the remaining 90 percent into heat. (A fluorescent light bulb will give the same amount of light while consuming only one-fourth of the electrical energy, and it will last 10 times longer than an incandescent light bulb.) The glass bulb of the lamp heats up very quickly as a result of absorbing all that heat and dissipating it to the surroundings by convection and radiation. Consider a 0.525-m-diameter 100-W light bulb cooled by a fan that blows air at 30°C to the bulb at a velocity of 306 m/s. The surrounding surfaces are also at 30°C, and the emissivity of the glass is 0.9. Assuming 10 percent of the energy passes through the glass bulb as light with negligible absorption and the rest of the energy is absorbed and dissipated by the bulb itself, determine the equilibrium temperature of the glass bulb. Assume a surface temperature of 100°C for evaluation of µs- The properties of air at 1 atm pressure and the free stream temperature of 30°C are k = 0.02588 W/m°C, v = 1.608x1o-5 m²/s, µoo = 1.872x10-5 kg/m.s, Hs at 100°C = 2.181x10-5 kg/m.s, and Pr = 0.7282. 100 W 3 = 0.9* Light, 10 W
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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