An impala is running away from a hunting lion in pursuit. To evade capture and certain death, the impala decides to jump from a tall ledge to a lower terrain. The ledge has a 6 m drop (i.e., the impala lands at a lower height than where it jumped). If the impala runs with a velocity of 15 m/s and leaps horizontally. How long is the impala in the air before landing? (round to the nearest one-hundredth)What will the impala's horizontal displacement be when it lands? (round to the nearest one-hundredth)What is the impala's final velocity as it lands? HINT: you need both the x- and y-components of the velocity to find the total final velocity! (round to the nearest one-hundredth)

Name: An impala is running away from a hunting lion in pursuit. To evade cap
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Description: An impala is running away from a hunting lion in pursuit. To evade capture and certain death, the impala decides to jump from a tall ledge to a lower terrain. The ledge has a 6 m drop (i.e., the impala lands at a lower height than where it jumped). I

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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An impala is running away from a hunting lion in pursuit. To evade capture and certain death, the impala decides to jump from a tall ledge to a lower terrain. The ledge has a 6 m drop (i.e., the impala lands at a lower height than where it jumped). If the impala runs with a velocity of 15 m/s and leaps horizontally.

How long is the impala in the air before landing? (round to the nearest one-hundredth)
What will the impala's horizontal displacement be when it lands? (round to the nearest one-hundredth)
What is the impala's final velocity as it lands? HINT: you need both the x- and y-components of the velocity to find the total final velocity! (round to the nearest one-hundredth)

Expert Solution

Step 1

At the point of jump,

The x component of the velocity: $v_{x} (0) = 15 m / s$ .

The y component of the velocity: $v_{y} (0) = 0$

vertical drop = 6m

For motion in x - direction we have

$x (t) = v_{x} (0) t$ ----(1)

For motion in y- direction we have

$y (t) = 6 - \frac{1}{2} g t^{2}$ ----(2)

Here we have assumed that initially the impala is running at y=6 m level and drops to y=0 after the jump.

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