An image of an object is formed on a screen by a lens. Leaving the lens fixed the object is moved to a new position and the screen moved until it again receives a focused image. If the two object distances are pi and p2, and if the transverse magnifications of the images are M1 and M2, respectively, show that the focal length of the lens is given by (P2 – P1) 1 M1 M2
Q: An object is 20 cm in front of a diverging lens that has a focal length of -9.4 cm. How far in front…
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Q: The focal length of a diverging lens is negative. If f = −30 cm for a particular diverging lens,…
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Q: A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -40 cm…
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Q: A certain slide projector has a 150 mm focal length lens. (a)How far away is the screen (in m), if…
A: Solution: Given, focal lengthf = 150 mm = 0.115 mdistance of object = u = 158mm = 0158m
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Q: There is a lens combinations between two converging lenses that have focal lengths of f1=13 cm (lens…
A: Converging lens is the type of lens which is curved outward from both the sides. Converging lens are…
Q: You have a concave (diverging) lens with a −35 cm focal length. The magnification produced by the…
A: The u-v-f relation for lens is 1v-1u=1f ....(1) The magnification is m=vu .....(2) Here…
Q: The projection lens in a certain slide projector is a single thin lens. A slide 23.6 mm high is to…
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Q: focal length of a diverging lens is negative. If f = −18 cm for a particular diverging lens, where…
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Q: If two lenses A and B have exactly the same values of R1 and R2, but A is made of a material with…
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Q: An object with a height of -0.060 m points below the principal axis (it is inverted) and is 0.180 m…
A: Step 1:Step 2:Step 3:
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Q: An object has a height of 0.067 m and is held 0.220 m in front of a converging lens with a focal…
A: Heights of object =0.067mObject distance =0.22mFocal length =0.19m
Q: An object has a height of 0.046 m and is held 0.220 m in front of a converging lens with a focal…
A: We use the real is positive sign convention
Q: The focal length of a diverging lens is negative. If f = −24 cm for a particular diverging lens,…
A: From the thin lens formula.
Q: Two lenses are mounted d = 28 cm apart on an optical bench. The focal length of the first lens is f1…
A: Distance between two lenses, d=28cmFocal length of the first lens, focal length of the second lens,…
Q: The focal length of a diverging lens is negative. If f = −27 cm for a particular diverging lens,…
A: Focal length of lens,(F)=-27 cm -------(1) [Given] Object distance,(U)=-62 cm -------(2) [Given]…
Q: An object has a height of 0.051 m and is held 0.220 m in front of a converging lens with a focal…
A: Given that, Height of the object, ho=0.051 m Object distance, u=0.220 m The focal length of the…
Q: object is placed a distance of 4.16f from a converging lens, where f is the lens's focal length.…
A: Given u = - 4.16 fHere, ' f ' is the focal length of the converging lens.
Q: An object with a height of -0.060 m points below the principal axis (it is inverted) and is 0.110 m…
A: Height of object h1 = -0.060 mDistance of object u = 0.110 mFocal length of lens f = -0.35 mLet…
Q: For a given converging lens, an object placed 1.15 m away from the lens produces an image 0.28 m…
A: Given data The object distance is given as u = -1.15 m. The image distance is given as v = -0.28 m.…
Q: The focal length of a diverging lens is negative. If f = −18 cm for a particular diverging lens,…
A: Given:- The focal length of the diverging lens is f = -18 cm. The object distance for the diverging…
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A: We will use 'real is positive' convention for lens formula (not the cartesian one). in air u=1, v…
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Q: (5) A compound microscope is made with an objective lens (fo = 1.000 cm) and an eyepiece (fe = 0.500…
A: Hello. Since you have posted multiple questions and not specified which question needs to be solved,…
Q: There is a lens combinations between two converging lenses that have focal lengths of f1=13 cm (lens…
A: The image formed by lens 1 acts as an object for lens 2 which then forms the image that is observed…
Q: A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -40 cm…
A: Given Data: Focal length of converging lens is f1=40 cm Focal length of diverging lens is f2=-40 cm…
Q: The projection lens in a certain slide projector is a single thin lens. A slide 23.4 mm high is to…
A: Height of object (slide), h=23.4 mm = 0.0234 m Height of image, h'= 1.84 m Negaun The…
Q: Two converging lenses, both with focal lengths 34.5 cm are placed a distance 78.3 cm apart. An…
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Q: An object of height 7.25 cm is placed at a distance of 22.5 cm from the convex lens. Whose focal…
A: Given Type of lens is convex the focal length of lens is 10.5 centimetre the height of object is…
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A: The given expression from lens formula,
Q: An object with a height of -0.040 m points below the principal axis (it is inverted) and is 0.200 m…
A: Height of object h1 = -0.040 m Distance of object u = -0.200 m Focal length of lens f = -0.27 m Let…
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- A lens of focal length +24.0 cm is at x 0, and a second lens of focal length -24.0 cm is located at x = 16.0 cm. Let the positive x-direction be to the right. At what position x is the final image of an object that is 48.0 cm to the left of the positive lens? cm X = What is the magnification m of the image?.(Remember that magnification can be positive or negative.) m = The image is and virtual real Where should your eye be located and directed to see the image? O looking left from the right of both lenses looking left from between the lenses looking right from between the lenses O looking right from the left of both lenses Question Source: Freedman College PhysicThe focal length of a diverging lens is negative. If f = −30 cm for a particular diverging lens, where will the image be formed of an object located 36 cm to the left of the lens on the optical axis? cm to the left of the lensWhat is the magnification of the image?The focal length of a diverging lens is negative. If f = −16 cm for a particular diverging lens, where will the image be formed of an object located 45 cm to the left of the lens on the optical axis? cm to the left of the lensWhat is the magnification of the image?
- An object with a height of -0.040 m points below the principal axis (it is inverted) and is 0.140 m in front of a diverging lens. The focal length of the lens is -0.25 m. (Include the sign of the value in your answers.) (a) What is the magnification? (b) What is the image height? m (c) What is the image distance? mA 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 7.80 cm. A diverging lens of focal length –16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 7.5 cm in front of the second lens v 0.5466 height Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm Is the image inverted or upright? upright O inverted Is the image real or virtual? real virtualTwo converging lenses, both with focal lengths 34.9 cm are placed a distance 78.9 cm apart. An object is placed 87.5 cm from the 1st lens. Where is the final image located relative to the 2nd lens? Let + be the back side and - be the front side regarding this distance from the 2nd lens. Measure this in cm.
- An object of 1 cm tall is placed 3cm in front of a converging lens of focal length of 2 cm. (a) Use ray tracing to find the image. (b) Use the lens equation to find the image distance and compare it to your ray tracing and find the percentage error.An object is 21 cm in front of a diverging lens that has a focal length of -9.6 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 2.6?A lens of focal length 42 mm is used as a magnifier. The object being viewed is 6.8 mm long, and is positioned at the focal point of the lens. The lens is moved closer to the object, so that the image is now 15 cm from the lens. The distance the lens has been moved, in cm, is closest to: