An ideal gas expands in a reversible and adiabatic process. What will happen to the temperature of the gas? Question 12 options: The temperature will rise The temperature will fall There will be no change in temperature The final temperature will be zero

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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A bimolecular heterogeneous catalytic reaction: A(g) +B(g) →P showed that the rate increased at low pA
and then the rate decreased at high pA when pB was kept constant. A similar trend was observed with
change in pB at constant pA. What is the rate law?
Question 11 options:
r=K2KA pA KB pB
r= (K2KA PA pB) /(1+ KA pA)
r=(K2KA PA KB pB) /( 1+ KA PA + KB pB)2
r=(K2KA PA KB pB) /( 1+ KA PA + KB pB)
Transcribed Image Text:A bimolecular heterogeneous catalytic reaction: A(g) +B(g) →P showed that the rate increased at low pA and then the rate decreased at high pA when pB was kept constant. A similar trend was observed with change in pB at constant pA. What is the rate law? Question 11 options: r=K2KA pA KB pB r= (K2KA PA pB) /(1+ KA pA) r=(K2KA PA KB pB) /( 1+ KA PA + KB pB)2 r=(K2KA PA KB pB) /( 1+ KA PA + KB pB)
An ideal gas expands in a reversible and adiabatic process. What will happen to the temperature of the
gas?
Question 12 options:
The temperature will rise
The temperature will fall
There will be no change in temperature
The final temperature will be zero
Transcribed Image Text:An ideal gas expands in a reversible and adiabatic process. What will happen to the temperature of the gas? Question 12 options: The temperature will rise The temperature will fall There will be no change in temperature The final temperature will be zero
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