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An ideal diatomic gas has an initial pressure of 1.00×10°Pa , an initial volume of 2.00m° , and an initial temperature of 300K. (This is point 1 on the pV-diagram.) The gas has an isochoric increase in pressure to 2.00×10° Pa. (This is point 2 on the pV-diagram.) The gas then has an isothermal expansion to a volume of 3.00m' . (This is point 3 on the pV-diagram.) The pressure is then reduced adiabatically back down to its original pressure of 1.00×10°P.. (This is point 4 on the pV-diagram.) Finally, the gas has an isobaric decrease in volume to its original volume of 2.00m. (The gas is back to point 1 on the pV-diagram.) Fill in the missing values on the following table. а. Point Volume Pressure. Temnerature

An ideal diatomic gas has an initial pressure of 1.00×10°Pa , an initial volume of 2.00m° , and an initial temperature of 300K. (This is point 1 on the pV-diagram.) The gas has an isochoric increase in pressure to 2.00×10° Pa. (This is point 2 on the pV-diagram.) The gas then has an isothermal expansion to a volume of 3.00m' . (This is point 3 on the pV-diagram.) The pressure is then reduced adiabatically back down to its original pressure of 1.00×10°P.. (This is point 4 on the pV-diagram.) Finally, the gas has an isobaric decrease in volume to its original volume of 2.00m. (The gas is back to point 1 on the pV-diagram.) Fill in the missing values on the following table. а. Point Volume Pressure. Temnerature

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An ideal diatomic gas has an initial pressure of 1.00×10°Pa , an initial volume of 2.00m', and an initial temperature of 300K. (This is point 1 on the pV-diagram.) The gas has an isochoric increase in pressure to 2.00×10°P. . (This is point 2 on the pV-diagram.) The gas then has an isothermal expansion to a volume of 3.00m'. (This is point 3 on the pV-diagram.) The pressure is then reduced adiabatically back down to its original pressure of 1.00×10°P.. (This is point 4 on the pV-diagram.) Finally, the gas has an isobaric decrease in volume to its original volume of 2.00m. (The gas is back to point 1 on the pV-diagram.) а. Fill in the missing values on the following table. Point Volume, Pressure, Temperature, v (m²) p(10ʻPA) T(K) 1 2.00 1.00 300 2 2.00 3 3.00 4 1.00 b. Fill in the values for each of the processes in the following table. (These values correspond to the First Law of Thermodynamics written as: AE, =W +Q.) Process Change in internal Work done to gas, Heat added to gas, energy, AE, (J) W (3) Q(1) 'th 1→ 2 2 → 3 3 → 4 4 →1 Full Cycle
Transcribed Image Text:An ideal diatomic gas has an initial pressure of 1.00×10°Pa , an initial volume of 2.00m', and an initial temperature of 300K. (This is point 1 on the pV-diagram.) The gas has an isochoric increase in pressure to 2.00×10°P. . (This is point 2 on the pV-diagram.) The gas then has an isothermal expansion to a volume of 3.00m'. (This is point 3 on the pV-diagram.) The pressure is then reduced adiabatically back down to its original pressure of 1.00×10°P.. (This is point 4 on the pV-diagram.) Finally, the gas has an isobaric decrease in volume to its original volume of 2.00m. (The gas is back to point 1 on the pV-diagram.) а. Fill in the missing values on the following table. Point Volume, Pressure, Temperature, v (m²) p(10ʻPA) T(K) 1 2.00 1.00 300 2 2.00 3 3.00 4 1.00 b. Fill in the values for each of the processes in the following table. (These values correspond to the First Law of Thermodynamics written as: AE, =W +Q.) Process Change in internal Work done to gas, Heat added to gas, energy, AE, (J) W (3) Q(1) 'th 1→ 2 2 → 3 3 → 4 4 →1 Full Cycle
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