An ice cream shop finds that its weekly profit P (in dollars) as a function of the price a (in dollars) it charges per ice cream cone is given by the function g, defined by g(x) = – 110z? + 700x – 120. a. What price should the store charge to maximize their profit? Need a hint? $ 35/11 Preview b. According to the model, what is the store's maximum weekly profit? Need a hint? $ 10930/11 Preview c. What prices would cause the weekly profit to be $0? (Write your answers as a comma-separated list.) Need a hint? $ 6.18,0.18 Preview

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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### Ice Cream Shop Profit Model

An ice cream shop finds that its weekly profit \( P \) (in dollars) as a function of the price \( x \) (in dollars) it charges per ice cream cone is given by the function \( g \), defined by:

\[ g(x) = -110x^2 + 700x - 120 \]

**a. Maximizing Profit**

- **Question:** What price should the store charge to maximize their profit?
- **Answer:** \( \frac{35}{11} \)

**b. Maximum Weekly Profit**

- **Question:** According to the model, what is the store's maximum weekly profit?
- **Answer:** \( \frac{10930}{11} \)

**c. Prices for Zero Profit**

- **Question:** What prices would cause the weekly profit to be $0? (Write your answers as a comma-separated list.)
- **Answer:** \( 6, 18, 0.18 \)

**d. Comparison with Another Store's Model**

Another ice cream shop developed a similar model for their weekly profit. Its model is \( f \) where:

\[ f(x) = g(x) + 475 \]

**Implications:**

- ✔️ When this shop charges the same price per ice cream cone, it will always earn an additional $475 per week compared to the original store.
- ❌ When this shop charges the same price per ice cream cone, it will always earn $475 per week less than the original store.
- ✔️ The two stores have different maximum weekly profits.
- ✔️ To maximize weekly profits, both stores should charge the same price per cone. 

This exercise illustrates how changing the pricing model impacts the profitability of a business.
Transcribed Image Text:### Ice Cream Shop Profit Model An ice cream shop finds that its weekly profit \( P \) (in dollars) as a function of the price \( x \) (in dollars) it charges per ice cream cone is given by the function \( g \), defined by: \[ g(x) = -110x^2 + 700x - 120 \] **a. Maximizing Profit** - **Question:** What price should the store charge to maximize their profit? - **Answer:** \( \frac{35}{11} \) **b. Maximum Weekly Profit** - **Question:** According to the model, what is the store's maximum weekly profit? - **Answer:** \( \frac{10930}{11} \) **c. Prices for Zero Profit** - **Question:** What prices would cause the weekly profit to be $0? (Write your answers as a comma-separated list.) - **Answer:** \( 6, 18, 0.18 \) **d. Comparison with Another Store's Model** Another ice cream shop developed a similar model for their weekly profit. Its model is \( f \) where: \[ f(x) = g(x) + 475 \] **Implications:** - ✔️ When this shop charges the same price per ice cream cone, it will always earn an additional $475 per week compared to the original store. - ❌ When this shop charges the same price per ice cream cone, it will always earn $475 per week less than the original store. - ✔️ The two stores have different maximum weekly profits. - ✔️ To maximize weekly profits, both stores should charge the same price per cone. This exercise illustrates how changing the pricing model impacts the profitability of a business.
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