An fictitious element with the symbol Z, combines with oxygen to make an ion with the formula: Z2054 What is the oxidation number of Z in this ion? 6. 3. 4.
An fictitious element with the symbol Z, combines with oxygen to make an ion with the formula: Z2054 What is the oxidation number of Z in this ion? 6. 3. 4.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question: Oxidation Number Determination**
An fictitious element with the symbol Z combines with oxygen to make an ion with the formula: \( \text{Z}_2\text{O}_5^{4-} \).
What is the oxidation number of Z in this ion?
- ○ 5
- ○ 3
- ○ 6
- ○ 2
- ○ 4
**Explanation**:
To determine the oxidation number of Z in the ion \( \text{Z}_2\text{O}_5^{4-} \), use the following steps:
1. **Determine the oxidation number of oxygen**: Oxygen typically has an oxidation number of -2.
2. **Apply the formula**:
- In \( \text{Z}_2\text{O}_5^{4-} \), there are 5 oxygen atoms.
- Total oxidation from oxygen: \( 5 \times (-2) = -10 \).
3. **Consider the overall charge**:
- The ion has a charge of -4. This means the combined oxidation amount from Z must counterbalance the charge from oxygen to result in an overall charge of -4.
4. **Set up the equation** for total charge balance:
- Let the oxidation number of Z be \( x \).
- \( 2x + (-10) = -4 \)
- Solve for \( x \):
\[
2x - 10 = -4
\]
\[
2x = 6
\]
\[
x = 3
\]
Thus, the oxidation number of Z in the ion is 3.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6501bcec-69f0-41c7-aaf6-9d4563ecc7cd%2F4fa2275b-e3f3-4621-bc87-3e8c49f0a44b%2Fdt0ezck_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question: Oxidation Number Determination**
An fictitious element with the symbol Z combines with oxygen to make an ion with the formula: \( \text{Z}_2\text{O}_5^{4-} \).
What is the oxidation number of Z in this ion?
- ○ 5
- ○ 3
- ○ 6
- ○ 2
- ○ 4
**Explanation**:
To determine the oxidation number of Z in the ion \( \text{Z}_2\text{O}_5^{4-} \), use the following steps:
1. **Determine the oxidation number of oxygen**: Oxygen typically has an oxidation number of -2.
2. **Apply the formula**:
- In \( \text{Z}_2\text{O}_5^{4-} \), there are 5 oxygen atoms.
- Total oxidation from oxygen: \( 5 \times (-2) = -10 \).
3. **Consider the overall charge**:
- The ion has a charge of -4. This means the combined oxidation amount from Z must counterbalance the charge from oxygen to result in an overall charge of -4.
4. **Set up the equation** for total charge balance:
- Let the oxidation number of Z be \( x \).
- \( 2x + (-10) = -4 \)
- Solve for \( x \):
\[
2x - 10 = -4
\]
\[
2x = 6
\]
\[
x = 3
\]
Thus, the oxidation number of Z in the ion is 3.
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