An extreme skier, starting from rest, coasts down a mountain slope that makes an angle of 25.0° with the horizontal. The coefficient of kinetic friction between her skis and the snow is 0.200. She coasts down a distance of 10.4m before coming to the edge of a cliff. Without slowing down, she skis off the cliff and lands downhill at a point that is vertically 3.50m below the edge. What will be her landing speed?
An extreme skier, starting from rest, coasts down a mountain slope that makes an angle of 25.0° with the horizontal. The coefficient of kinetic friction between her skis and the snow is 0.200. She coasts down a distance of 10.4m before coming to the edge of a cliff. Without slowing down, she skis off the cliff and lands downhill at a point that is vertically 3.50m below the edge. What will be her landing speed?
Related questions
Question
Transcribed Image Text:An extreme skier, starting from rest, coasts down a mountain slope that makes an
angle of 25.0° with the horizontal. The coefficient of kinetic friction between her
skis and the snow is 0.200. She coasts down a distance of 10.4m before coming
to the edge of a cliff. Without slowing down, she skis off the cliff and lands
downhill at a point that is vertically 3.50m below the edge. What will be her
landing speed?
Answer: W = mg (s sin 0+Ah)– µsmg cos 0 =m(v, -v)
net
m
s =10.4m, Ah=3.5m, 0=25°, v; = 0-
gives v, =10.9-
S
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps
