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An experimental strain gauge is mounted on a 0.25mm diameter metal bar (circular cross section) in the axial direction. The gauge has a measured resistance of 120 Ohms. When the bar is loaded with 500*P N in tension, the gauge resistance increases by 0.01 Ohms. What is the gauge factor of the gauge? Assume that the Young’s modulus of the metal bar is equal to 120 GPa (Giga Pascal). Note that 1 Pa = 1 N/m2 (Newton per square meter) and assume P is 4.

An experimental strain gauge is mounted on a 0.25mm diameter metal bar (circular cross section) in the axial direction. The gauge has a measured resistance of 120 Ohms. When the bar is loaded with 500*P N in tension, the gauge resistance increases by 0.01 Ohms. What is the gauge factor of the gauge? Assume that the Young’s modulus of the metal bar is equal to 120 GPa (Giga Pascal). Note that 1 Pa = 1 N/m2 (Newton per square meter) and assume P is 4.

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An experimental strain gauge is mounted on a 0.25mm diameter metal bar (circular cross
section) in the axial direction. The gauge has a measured resistance of 120 Ohms. When the
bar is loaded with 500*P N in tension, the gauge resistance increases by 0.01 Ohms. What
is the gauge factor of the gauge? Assume that the Young’s modulus of the metal bar is
equal to 120 GPa (Giga Pascal). Note that 1 Pa = 1 N/m2 (Newton per square meter) and assume P is 4.

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after simplify, why 120 ohms is removed but not the L ?

Enter the values: ε = (500 * 4 N * L) / (π * (0.00025 m)^2 * 120 * 10^9 Pa) / L Now, calculate the gauge factor (GF): GF = AR/(R* E) GF = (0.01 Ohms) / (120 Ohms * [(500 * 4 N * L) / (π * (0.00025 m)^2 * 120 * 10^9 Pa)] / L) Simplify: GF = 0.01 Ohms / ((500 * 4 N * L) / π * (0.00025 m)^2 * 120 * 10^9 Pa)] Put the values in and calculate: GF≈ 5.24 Strain gauge gauge factor is 5.24.
Transcribed Image Text:Enter the values: ε = (500 * 4 N * L) / (π * (0.00025 m)^2 * 120 * 10^9 Pa) / L Now, calculate the gauge factor (GF): GF = AR/(R* E) GF = (0.01 Ohms) / (120 Ohms * [(500 * 4 N * L) / (π * (0.00025 m)^2 * 120 * 10^9 Pa)] / L) Simplify: GF = 0.01 Ohms / ((500 * 4 N * L) / π * (0.00025 m)^2 * 120 * 10^9 Pa)] Put the values in and calculate: GF≈ 5.24 Strain gauge gauge factor is 5.24.
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