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An experiment was conducted to compare broadleaf seedling growth by treating the seedling soil weeds with one of two fertilizers. Thirty of 75 seedlings were randomly chosen to receive Fertilizer X. The rest received Fertilizer Y. The heights were recorded for each seedling, in centimeters, at the end of the study. The results obtained are shown. Fertilizer X: X₁ = 72.4 cm, s₁ = 9 cm Fertilizer Y: X2=86.1 cm, s₂ = 8 cm We wish to determine whether there is a difference in height for the seedlings treated with the different herbicides. To answer this question, we decide to test the hypotheses Ho: H2 - H₁ = 0 and Ha: H2 - μ1 # 0. Find the 95% confidence interval for μ2 - μ₁ and make a conclusion based on that confidence interval. O The 95% confidence interval is 13.7 ± 4.065. I would not reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 9.63. I would not reject the null hypothesis of no difference at the 0.05 level. ○ The 95% confidence interval is 13.7 ± 4.065. I would reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 9.63. I would reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 17.75. The p-value is less than 0.05.

An experiment was conducted to compare broadleaf seedling growth by treating the seedling soil weeds with one of two fertilizers. Thirty of 75 seedlings were randomly chosen to receive Fertilizer X. The rest received Fertilizer Y. The heights were recorded for each seedling, in centimeters, at the end of the study. The results obtained are shown. Fertilizer X: X₁ = 72.4 cm, s₁ = 9 cm Fertilizer Y: X2=86.1 cm, s₂ = 8 cm We wish to determine whether there is a difference in height for the seedlings treated with the different herbicides. To answer this question, we decide to test the hypotheses Ho: H2 - H₁ = 0 and Ha: H2 - μ1 # 0. Find the 95% confidence interval for μ2 - μ₁ and make a conclusion based on that confidence interval. O The 95% confidence interval is 13.7 ± 4.065. I would not reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 9.63. I would not reject the null hypothesis of no difference at the 0.05 level. ○ The 95% confidence interval is 13.7 ± 4.065. I would reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 9.63. I would reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 17.75. The p-value is less than 0.05.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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An experiment was conducted to compare broadleaf seedling growth by treating the seedling soil weeds with one of two fertilizers. Thirty of 75 seedlings were randomly chosen to receive Fertilizer X. The rest received Fertilizer Y. The heights were recorded for each seedling, in centimeters, at the end of the study. The results obtained are shown. Fertilizer X: X₁ = 72.4 cm, s₁ = 9 cm Fertilizer Y: X2=86.1 cm, s₂ = 8 cm We wish to determine whether there is a difference in height for the seedlings treated with the different herbicides. To answer this question, we decide to test the hypotheses Ho: H2 - H₁ = 0 and Ha: H2 - μ1 # 0. Find the 95% confidence interval for μ2 - μ₁ and make a conclusion based on that confidence interval. O The 95% confidence interval is 13.7 ± 4.065. I would not reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 9.63. I would not reject the null hypothesis of no difference at the 0.05 level. ○ The 95% confidence interval is 13.7 ± 4.065. I would reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 9.63. I would reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 17.75. The p-value is less than 0.05.
Transcribed Image Text:An experiment was conducted to compare broadleaf seedling growth by treating the seedling soil weeds with one of two fertilizers. Thirty of 75 seedlings were randomly chosen to receive Fertilizer X. The rest received Fertilizer Y. The heights were recorded for each seedling, in centimeters, at the end of the study. The results obtained are shown. Fertilizer X: X₁ = 72.4 cm, s₁ = 9 cm Fertilizer Y: X2=86.1 cm, s₂ = 8 cm We wish to determine whether there is a difference in height for the seedlings treated with the different herbicides. To answer this question, we decide to test the hypotheses Ho: H2 - H₁ = 0 and Ha: H2 - μ1 # 0. Find the 95% confidence interval for μ2 - μ₁ and make a conclusion based on that confidence interval. O The 95% confidence interval is 13.7 ± 4.065. I would not reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 9.63. I would not reject the null hypothesis of no difference at the 0.05 level. ○ The 95% confidence interval is 13.7 ± 4.065. I would reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 9.63. I would reject the null hypothesis of no difference at the 0.05 level. O The 95% confidence interval is 13.7 ± 17.75. The p-value is less than 0.05.
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