An equilibrium mixture contains 1.50 mol of nitrogen, 4.45 mol of hydrogen and 7.05 mol of ammonia in a 5.00-L reaction vessel. Calculate the K. for the reaction shown below: N2 (g) + 3 H₂ (g) = 2 NH3 (g)

Q: Suppose a 250.mL flask is filled with 0.80mol of CO, 0.60mol of NO and 0.20mol of CO2. The following…

A: Initial concentration of CO = number of mol/volume (L) = 0.80 mol /0.250 L = 3.2 MInitial…

Q: Suppose a 250. mL flask is filled with 0.60 mol of O₂ and 1.3 mol of NO. The following reaction…

A: Volume of the flask =  250 mL Initial moles of O2 = 0.60 moles     Moles of NO =  1.3 moles  Kc =…

Q: initial change equilibrium

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Q: Suppose a 500. mL flask is filled with 0.90 mol of CO, 1.3 mol of NO and 0.70 mol of CO₂. The…

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Q: Suppose a 500. mL flask is filled with 0.30 mol of CO, 0.10 mol of NO and 1.9 mol of CO2. The…

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Q: Consider the equilibrium system described by the chemical reaction below. A 1.00 L reaction vessel…

A: The ICE table for the given reaction can be made as follows,  As given that at equilibrium 1.30 mol…

Q: Consider the following reaction: 2 H20(g) + 2 SO2(g) = 2 H2S(g) + 3 O2(g) A reaction mixture…

A: In this question, we want to determine the value of Kc ( Equilibrium constant ) for a given…

Q: A mixture of 2.0 mol of CO (g) and 2.0 mol of H20 (g) was allowed to come to equilibrium in a 10.0-L…

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Q: Suppose a 250. mL flask is filled with 1.2 mol of H₂ and 0.90 mol of HI. This reaction becomes…

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Q: Given the following reaction at equilibrium at 300.0 K: NH,HS (s) = NH3 (g) + H2S (g) If PNH3 = PH2S…

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Q: Suppose a 250.mL flask is filled with 0.80mol of CO, 0.60mol of NO and 0.20mol of CO2. The following…

A: The initial concentrations of CO, NO and CO2 are calculated as shown below.250 mL = 0.250 L

Q: Consider the equilibrium reaction: 2SO2(g) + O2(g)---->2SO3(g). You place 1.00 mol/L each of SO2…

A: Given  2SO2(g)  +  O2(g)  →  2SO3 (g) Initial Concentration of SO2 and O2 = 1 mol/L  Equilibrium…

Q: 5.0 mole of ammonia were introduced into a 5.0L reaction chamber in which it is partially decomposed…

A: Ammonia = 5 moles Reacted moles = 80 % of 5 moles