An equation representing a vibrating string of one unit long, fixed at both ends, is given in Equation (T13.3). (T13.3) Equation (T13.3) can be written in the form of (T13.4) using the central finite difference approximation of the second derivative of their respective variables. The subscripts represent locations while superscripts represent time steps. The string is discretised into five nodes equally distanced, and At = 0.1. (T13.4) y = By₁₁+Cy+ Dy + Ey¹ a) Express B, C, D and E in numerical values. After that, write down three equations as a result of applying Equation (T13.4) to the domain. Subscripts must be replaced with correct node numbers, while the superscripts remain. You are not required to incorporate the boundary and initial conditions yet. (Answer: r = At/Ax = 0.1/0.25 = 0.4 B=0.16, C=1.68, D=0.16, E=-1) b) Assemble the three equations above in the form of matrix equation: {y}[4]{y}+{y}+{BC), where [4] is a square matrix, {BC) is a vector containing the boundary conditions, {y}",{y}', and {y} are vectors containing nodal variables at times +1, tand t-1, respectively. You are not required to incorporate the boundary and initial conditions yet. (Answer: [1.68 0.16 0y y's 0.16 1.68 0.16 y 2 0 0.16 1.68 c) Initially the string is at rest at the profile described in Figure T13.1. Find {y2 y3 y4} and {y2 y3 y4}. Show all the necessary calculations. (Answer: 1 1.68 (0.9488] 1.1424 and (0.9488

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 58E
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An equation representing a vibrating string of one unit long, fixed at both ends, is given
in Equation (T13.3).
(T13.3)
Equation (T13.3) can be written in the form of (T13.4) using the central finite difference
approximation of the second derivative of their respective variables. The subscripts
represent locations while superscripts represent time steps. The string is discretised into
five nodes equally distanced, and At = 0.1.
(T13.4)
y = By₁₁+Cy+ Dy + Ey¹
a) Express B, C, D and E in numerical values. After that, write down three
equations as a result of applying Equation (T13.4) to the domain. Subscripts
must be replaced with correct node numbers, while the superscripts remain. You
are not required to incorporate the boundary and initial conditions yet. (Answer:
r = At/Ax = 0.1/0.25 = 0.4
B=0.16, C=1.68, D=0.16, E=-1)
b) Assemble the three equations above in the form of matrix equation:
{y}[4]{y}+{y}+{BC), where [4] is a square matrix, {BC) is a vector
containing the boundary conditions, {y}",{y}', and {y} are vectors
containing nodal variables at times +1, tand t-1, respectively. You are not
required to incorporate the boundary and initial conditions yet. (Answer:
[1.68 0.16 0y
y's
0.16 1.68 0.16 y
2
0 0.16 1.68
c) Initially the string is at rest at the profile described in Figure T13.1. Find
{y2 y3 y4} and {y2 y3 y4}. Show all the necessary calculations.
(Answer:
1
1.68
(0.9488]
1.1424
and
(0.9488
Transcribed Image Text:An equation representing a vibrating string of one unit long, fixed at both ends, is given in Equation (T13.3). (T13.3) Equation (T13.3) can be written in the form of (T13.4) using the central finite difference approximation of the second derivative of their respective variables. The subscripts represent locations while superscripts represent time steps. The string is discretised into five nodes equally distanced, and At = 0.1. (T13.4) y = By₁₁+Cy+ Dy + Ey¹ a) Express B, C, D and E in numerical values. After that, write down three equations as a result of applying Equation (T13.4) to the domain. Subscripts must be replaced with correct node numbers, while the superscripts remain. You are not required to incorporate the boundary and initial conditions yet. (Answer: r = At/Ax = 0.1/0.25 = 0.4 B=0.16, C=1.68, D=0.16, E=-1) b) Assemble the three equations above in the form of matrix equation: {y}[4]{y}+{y}+{BC), where [4] is a square matrix, {BC) is a vector containing the boundary conditions, {y}",{y}', and {y} are vectors containing nodal variables at times +1, tand t-1, respectively. You are not required to incorporate the boundary and initial conditions yet. (Answer: [1.68 0.16 0y y's 0.16 1.68 0.16 y 2 0 0.16 1.68 c) Initially the string is at rest at the profile described in Figure T13.1. Find {y2 y3 y4} and {y2 y3 y4}. Show all the necessary calculations. (Answer: 1 1.68 (0.9488] 1.1424 and (0.9488
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