An engineering school reports that 54% of its students were male (M), 30% of its students were between the ages of 18 and 20 (A), and that 20% were both male and between the ages of 18 and 20. What is the probability of choosing a random student who is a female or between the ages of 18 and 20? Assume P(F) = P(not M). Your answer should be given to two decimal places

An engineering school reports that 54% of its students were male (M), 30% of its students were between the ages of 18 and 20 (A), and that 20% were both male and between the ages of 18 and 20. What is the probability of choosing a random student who is a female or between the ages of 18 and 20? Assume P(F) = P(not M). Your answer should be given to two decimal places

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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An engineering school reports that 53% of its students are male (M), 37% of its students are between the ages of 18 and 20 (A), and that 20% are both male and between the ages of 18 and 20. What is the probability of a random student being chosen who is a female and is not between the ages of 18 and 20? Your answer should be to two decimal places.
A researcher wants to find the factors affecting the probability that a person suffers from heart diseases. Let Age denote the age of the person, let BMI denote whether the BMI of the preson is above 30 (BMI = 1) or below 30 (BMI = 0), and let smoker denote whether the person is a smoker (smoker= 1) or not (smoker=0). She collects a random sample of 1,000 individuals from the general population and estimates the following logit regression: Pr(Heart disease Age, BMI, Smoker) - F(2.46 +0.05Age + 0.04BMI + 0.04 Smoker). (0.98) (1.09) (1.31) (1.31) Standard errors are given in parentheses. The binary dependent variable, Heart disease denotes the probability of a person suffering from heart disease keeping Age, BMI, and smoker constant. The predicted probability that Henry who is currently aged 58, whose BMI is above 30, and is a smoker, will suffer from a heart disease is (Round your answer to four decimal places.)
According to a study on teenage shopping behavior, it was found that 75% of female teens regularly shop in stores rather than shopping online. If a group of 6 female teenagers are selected at random, what is the probability that at least 3 of them regularly do their shopping in stores? (Round your answer to four decimal places.)
From the U.S. Census Bureau and the article “U.S. Prison Population Falls for Third Year” by B. Montopoli of CBS News, we found that about 1 in every 200 Americans are in prison. Suppose 500 Americans are randomly sampled. Let X represents the number of Americans currently in prison. n = λ = (Round to two decimal places) Calculate the probability that three of the 500 Americans are currently in prison. Round your answer to four decimal places, e.g., 0.XXXX or .XXXX. P(X = 3) = Calculate the probability that at least three of the 500 Americans are currently in prison. Round your answer to four decimal places, e.g., 0.XXXX or .XXXX. P (X ≥ 3) = 1 – P (X < 3) = Calculate E(X) = µ. Round your answer to two decimal places, e.g., 0.XX or .XX. µ = E(X) = Calculate the standard deviation of X. Round your answer to two decimal places, e.g., 0.XX or .XX. σ =
If a seed is planted, it has a 61% chance of growing into a healthy plant. Let X be the number of seeds grow into healthy plants when 57 seeds are planted. What is the distribution of X? Please show the following answers to 4 decimal places. What is the probability that exactly 24 seeds grow into healthy plants? What is the probability that at most 24 seeds grow into healthy plants?
In a certain year, the probability that a stock was in the Information Technology sector was 0.1353. The probability that the stock had a dividend yield of 2.00% or higher given that it was in the Information Technology sector was 0.2988. The probability that a stock had a dividend yield of 2.00% or higher given that it was not in the Information Technology sector was 0.4469. Find the probability that the stock was in the Information Technology sector given that it had a dividend yield of 2.00% or higher. Let F be the event that a stock was in the Information Technology sector and E be the event that a stock had a dividend yield of 2.00% or higher. P(F)= and P P (F') =
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A survey showed that 81% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 20 adults are randomly selected, find the probability that no more than 1 of them need correction for their eyesight. Is 1 a significantly low number of adults requiring eyesight correction? The probability that no more than 1 of the 20 adults require eyesight correction is (Round to three decimal places as needed.)
A pharmaceutical company is running trials on a new test for anabolic steroids. The company uses the test on 400 athletes known to be using steroids and 200 athletes known not to be using steroids. Of those using steroids, the new test is positive for 375 and negative for 25. Of those not using steroids, the test is positive for 25 and negative for 175. What is the relative frequency of a false negative result (the probability that an athlete using steroids will test negative)? (Round your answer to two decimal places.) What is the relative frequency of a false positive result (the probability that an athlete not using steroids will test positive)? (Round your answer to two decimal places.)
A survey showed that 79% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 15 adults are randomly selected, find the probability that at least 14 of them need correction for their eyesight. Is 14 a significantly high number of adults requiring eyesight correction? The probability that at least 14 of the 15 adults require eyesight correction is nothing. (Round to three decimal places as needed.)