↑ An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and 171 lb. The new population of pilots has normally distributed weights with a mean of 138 lb and a standard deviation of 27.3 lb. Standard normal distribution table (page 2) Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. ID a. If a pilot is randomly selected, find the probability that his weight is between 130 lb and 171 lb. The probability is approximately (Round to four decimal places as needed.) O Standard Normal (2) Distribution: Cumulative Area from the LEFT .00 .01 .06 2 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 .03 04 .05 5000 5040 5080 5120 5160 5199 5398 5438 5478 5517 5557 5239 .5279 496 5636 5675 5714 5793 .5832 5871 5910 5948 5987 6026 6064 6103 6179 6217 6255 .6293 .6331 6368 .6406 6443 6480 6554 6691 6628 6664 6700 6736 .6772 6808 6844 6915 6950 .6985 7019 .7054 .7068 7123 7157 .7190 7257 7291 7324 7357 7389 7422 7454 7486 7517 7580 7611 .7642 7673 7704 7734 7764 7794 .7823 7881 7910 .7939 7967 7995 8023 8051 8078 8106 8159 8186 8212 8238 8264 8289 8315 8340 8365 8413 8438 8461 8485 8508 8531 8554 8577 8599 8643 8665 8686 8708 8729 8749 8770 8790 8810 .02 .07 .08 .09 5319 5359 5753 6141 6517 6879 7224 7549 7852 8133 8389 8621 8830

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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e this View an example
alua....docx A
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An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and 171 lb. The new population of pilots has normally distributed weights
K with a mean of 138 lb and a standard deviation of 27.3 lb.
Click here to view page 1 of the standard normal distribution.
Click here to view page 2 of the standard normal distribution.
1
61
F1
Q
A
a. If a pilot is randomly selected, find the probability that his weight is between 130 lb and 171 lb.
The probability is approximately. (Round to four decimal places as needed.)
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#3
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Get more help.
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Transcribed Image Text:e this View an example alua....docx A ! An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and 171 lb. The new population of pilots has normally distributed weights K with a mean of 138 lb and a standard deviation of 27.3 lb. Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. 1 61 F1 Q A a. If a pilot is randomly selected, find the probability that his weight is between 130 lb and 171 lb. The probability is approximately. (Round to four decimal places as needed.) N @ 2 F2 W S #3 X I tion command H Get more help. 80 F3 E D $ 4 C a F4 R F % 5 V e FS T G 6 B MacBook Air G F6 Y H & 7 N 44 F7 U J * * 00 8 DII FO I M Standard normal distribution table (page 2) D Standard Normal (2) Distribution: Cumulative Area from the LEFT .01 .03 .05 .06 .07 5359 5753 6141 6517 6879 5000 5040 5080 5120 5160 5199 5239 5279 5319 5398 5438 .5478 5517 .5557 596 5636 5675 5714 5793 .5832 5871 5910 .5948 .5987 6026 .6064 6103 6179 .6217 .6255 .6293 .6331 .6368 .6406 6443 6480 .6554 .6591 6628 6664 6700 .6736 .6772 .6808 .6844 .6915 6950 .6985 .7019 .7054 .7088 .7123 .7157 .7190 7224 .7257 7291 .7324 .7357 .7389 7422 .7454 .7486 .7517 .7549 7580 .7611 7642 .7673 .7704 .7734 7764 7794 .7823 .7852 .7881 7910 .7939 .7967 .7995 8023 8051 8078 8106 8133 8159 8186 8212 8238 8264 8289 8315 8340 8365 .8389 8413 8438 8461 8485 8508 8531 8554 8577 8599 8621 .8643 .8665 8686 8708 8729 8749 .8770 8790 8810 8830 8849 8869 8888 8907 8925 .8944 8962 8980 8997 9015 9032 9049 9066 9082 9099 9115 9131 9147 9162 9177 9192 9207 9222 9236 9251 9265 9279 9292 9306 9319 9332 9345 9357 9370 9382 9394 9406 9418 9429 9441 9452 9463 9474 9484 9495 9505 9515 9525 9535 9545 9554 9564 .9573 9582 9591 9599 9608 9616 9625 9633 9641 9649 .9656 9664 9671 9678 9686 9693 9699 9706 0713 0710 4733 0744 6750 ATCC 0721 0770 0727 z 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 ( 9 K .00 DD F9 O I ) 0 .02 Print A F10 P . - : T L ; > I command option .04 F11 { Done [ ? 1 + = 11 F12 } ] Show All .08 delete .09 return shi
An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and 171 lb. The new population of pilots has normally distributed weights
K with a mean of 138 lb and a standard deviation of 27.3 lb.
Click here to view page 1 of the standard normal distribution.
Click here to view page 2 of the standard normal distribution.
this
a....docx A
FI
Q
A
1
an
View an example Get more help.
a. If a pilot is randomly selected, find the probability that his weight is between 130 lb and 171 lb
The probability is approximately. (Round to four decimal places as needed.)
Z
2
F2
W
S
X
command
#3
80
F3
E
D
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Q
R
F
%
5
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T
G
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6
B
MacBook Air
c
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Y
H
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Transcribed Image Text:An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and 171 lb. The new population of pilots has normally distributed weights K with a mean of 138 lb and a standard deviation of 27.3 lb. Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. this a....docx A FI Q A 1 an View an example Get more help. a. If a pilot is randomly selected, find the probability that his weight is between 130 lb and 171 lb The probability is approximately. (Round to four decimal places as needed.) Z 2 F2 W S X command #3 80 F3 E D $ 4 C Q R F % 5 V ļ F5 T G ^ 6 B MacBook Air c Fo Y H & 7 N F7 U J * 8 M Standard normal distribution table (page 1) - D₂₁ Standard Normal (z) Distribution: Cumulative Area from the LEFT .01 .02 .05 .06 .07 DII F8 z -3.50 and lower -3.4 -3.3 -3.2 -3.1 -3.0 -2.9 -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 -2.2 -2.1 -2.0 -1.9 -1.8 ( 9 K .00 DD F9 O < I .0003 .0003 .0003 0002 0003 .0005 0007 0010 .0001 .0003 ,0003 0003 .0003 .0003 ,0003 .0005 .0005 .0005 .0004 .0004 .0004 .0004 .0004 .0004 0007 .0007 .0006 0006 .0006 0006 .0006 .0005 .0005 .0010 0009 .0009 .0009 .0008 0008 .0008 .0007 .0008 .0013 .0013 .0013 0012 .0012 .0011 .0011 .0011 .0010 .0019 0018 0018 0017 .0016 .0016 .0015 .0015 .0014 0014 0026 .0025 0024 0023 0023 0022 .0021 .0021 0020 0019 0035 .0034 0033 0031 0032 0030 .0029 .0028 0027 .0026 .0047 .0045 0044 .0043 0041 0040 .0039 0038 0037 .0036 ,0062 .0060 .0059 .0057 0055 0054 0052 0051 0049 .0048 0082 .0080 .0078 0075 0073 .0071 .0069 .0068 .0066 .0064 0107 .0104 0102 .0099 .0096 0094 .0091 0089 0084 0087 0139 0136 0132 0129 0125 0122 .0119 .0116 0113 0110 .0174 0170 0166 0179 0162 0154 .0158 0228 0222 0217 0212 0207 0202 .0197 0287 0281 0274 0268 0262 0256 .0351 0344 0359 0336 0329 0322 .0314 0143 0183 0150 0146 0188 0192 0244 0250 0239 0301 0307 0233 0294 ) 0 L command .03 Print F10 E P : ; .04 2 option Done a F11 { w [ ? 1 + = I F12 } ] .08 Show All X 09 delete return shif
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