An engineer has received two bids for an elevator tobe installed in a new building. Given a 10% interestrate, which bid should be accepted?AlternativesInstalled costAnnual costSalvage valueLife, in yearsWestinghome$45,0002700300010Itis$54,0002850450015

Equivalent Annual Cost: It represents the annual cost of maintaining, operating, and owning the…

Answered: An engineer has received two bids for…

Essentials Of Investments

11th Edition

ISBN:9781260013924

Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Chapter1: Investments: Background And Issues

Section: Chapter Questions

Problem 1PS

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The Fence Company is setting up a new production line to create top rails. The relevant data for two alternatives are shown below. Flow Line Manufacturing Cell Installed Cost Expected Life Salvage Value Variable Cost per Top Rail Click here to access the TVM Factor Table Calculator $15,000 5 years $0 $6.00 $10,000 5 years $0 $7.00
3. You are confronted with a decision whether to replace an old transit mixer or to purchase a new one of the same model and capacity. The following information is given, namely: Replacement (Brand New) 3,200,000 65,000 300,000 15 year Retention (Refurbished) Initial Cost, P 550,000 Operating Cost, P/year Salvage value Life, year 210,000 30,000 5 Assuming interest rate is 6% per year, would you recommend to retain (with refurbishment) or to totally replace the equipment now? What are the implications of your decision? Explain your answer.
An existing asset that cost $16,000 twoyears ago has a market value of $12,000 today, anexpected salvage value of $2,000 at the end of itsremaining useful life of six more years, and annualoperating costs of $4,000. A new asset under consideration as a replacement has an initial cost of$10,000, an expected salvage value of $4,000 at theend of its economic life of three years, and annualoperating costs of $2,000. It is assumed that thisnew asset could be replaced by another one identical in every respect after three years at a salvagevalue of $4,000, if desired. Use a MARR of 11%,a six-year study period, and PW calculations todecide whether the existing asset should be replacedby the new one
Compare the following bridges on the basis of capitalized cost with i=14% effective.
The following annual costs are associated with three new extruder machines being considered for use in a Styrofoam cup plant: Data Useful Life, Years First Cost Salvage Value Annual Benefit M&O M&O Gradient X 17 $2,090,000 $87,000 $396,000 $56,000 $9,000 X-TRUD 13 $2,610,000 $93,000 $534,000 $60,000 $11,000 SUPR-X 11 $2,430,000 $119,000 $638,000 $53,000 $13,000 The company's interest rate (MARR) is 21%. Which extruder should the Styrofoam company choose? Use Annual Cash Flow Analysis and provide the right reason. Choosing SUPR-X is best because it has the lowest M&O cost in yr1 Choosing SUPR-X is best because it has the highest Annual Benefit Choosing SUPR-X will maximize the EUAB-EAUC; its value is $-127,486 higher than X and $15,650 higher than X-TRUD. Choosing SUPR-X will maximize the EUAB-EAUC; its value is $117,514 higher than X and $126,650 higher than X-TRUD.
expense of $500. Consider a yearly Two machines are evaluated for a new project, consider a yearly interest rate of 6% and the information described in the following table. Determine EUAC for both alternatives and determine the best option. Purchase cost Salvage value Duration Machine A Machine B $10,000 $15,000 $1,250 $1,950 5 years 10 years 11 13 L
Compare three alternatives on the basis of their capitalized costs at /= 8% per year and select the best alternative. Alternative E F G $-460,000 $-30,000 $90,000 4 First Cost AOC, per Year Salvage Value Life, Years $-80,000 $-65,000 $40,000 2 The capitalized cost of alternative E is $ The best alternative is (Click to select) ▼ alternative F is $ $-960,000 $-3,000 $450,000 ∞0 and alternative G is $
Problems 43 and 44 are based on the following statement: Used New machine machine Initial Cost 15,000 40,000 ($) Annual 8,000 2,000 operating cost ($/year) Salvage 5,000 10,000 value ($) Life (years) 3 6 Use an interest rate of 10% per year 43. The present worth of the new machine is closest to: (A) $43,630 (B) $43,066 (C) $45,210 (D) $49,660 44. To compare the machines on the basis of a present worth analysis, the present worth values to use are: (A) PWused $31,139, PW new = $43,066 (B) PWused $31,139, PW new = $37,461 (C) PWused $54,533, PW new = $43,066 (D) PWused $54,533, PW new = $37,461
RR
1. Determine the NPV of the new computer system (use 3 decimal places for the PV factor)
Acquisition of a new machine cost #680,000. Delivery, installation, and other expenses cost 15% of the purchasing cost. The machine has a useful life of 15 years with a scrap value of P85,000. Using the SYD method, what is the book value of the machine after 13 years? A P127,056.50 B P102,425.00 C P144,026.90 D P115,500.10

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An engineer has received two bids for an elevator to be installed in a new building. Given a 10% interest rate, which bid should be accepted? Alternatives Installed cost Annual cost Salvage value Life, in years Westinghome $45,000 2700 3000 10 Itis $54,000 2850 4500 15