An engine operates on a Brayton cycle with an air pressure ratio of 10 and flow rate 1 kg/s. If heat added to the cycle is 5,000 kJ and heat exhausted out from the cycle is 2,500 KJ, estimate the efficiency difference (%) in hot condition and in air standard assumptions, respectively, based on the hot condition. 273 K+ Jost
An engine operates on a Brayton cycle with an air pressure ratio of 10 and flow rate 1 kg/s. If heat added to the cycle is 5,000 kJ and heat exhausted out from the cycle is 2,500 KJ, estimate the efficiency difference (%) in hot condition and in air standard assumptions, respectively, based on the hot condition. 273 K+ Jost
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:**Brayton Cycle Efficiency Analysis**
An engine operates on a Brayton cycle with an air pressure ratio of 10 and a flow rate of 1 kg/s. If heat added to the cycle is 5,000 kJ and heat exhausted out from the cycle is 2,500 kJ, estimate the efficiency difference (%) in hot conditions and in air standard assumptions, respectively, based on the hot condition.
**Diagram Explanation**
The graph shown is a Temperature (T) vs. Entropy (s) diagram for the Brayton cycle. It is represented by four key points:
- **Point 1 to 2:** Isentropic (constant entropy) compression process.
- **Point 2 to 3:** Heat addition at constant pressure (represented by \( q_{in} \)).
- **Point 3 to 4:** Isentropic expansion process.
- **Point 4 to 1:** Heat rejection at constant pressure (represented by \( q_{out} \)).
The cycle begins at 273 K (indicated for reference on the temperature axis). The hatched areas visually indicate the processes of heat addition and rejection within the cycle.
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