"An engine manufacturer makes the claim that the engine they have developed will, on each cycle, take 100 J of heat out of boiling water at 100°C, do mechanical work of 80 J, and exhaust 20 J of heat at 10°C. What, if anything, is wrong with this claim?" The heat exhausted must always be greater than the work done according to the second law of thermodynamics. This engine violates the first law of thermodynamics because 100 J + 20 J ? 80 J. An engine would operate by taking in heat at the lower temperature and exhausting heat at the higher temperature. The efficiency of this engine is greater than the ideal Carnot cycle efficiency.

Given : Heat taken , Q1 = 100 J Mechanical Work, W = 80 J Heat out, Q2= 20 J Temperature of…

Answered: "An engine manufacturer makes the claim…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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"An engine manufacturer makes the claim that the engine they have developed will, on each cycle, take 100 J of heat out of boiling water at 100°C, do mechanical work of 80 J, and exhaust 20 J of heat at 10°C. What, if anything, is wrong with this claim?"

		The heat exhausted must always be greater than the work done according to the second law of thermodynamics.
		This engine violates the first law of thermodynamics because 100 J + 20 J ? 80 J.
		An engine would operate by taking in heat at the lower temperature and exhausting heat at the higher temperature.
		The efficiency of this engine is greater than the ideal Carnot cycle efficiency.

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