An energy company wants to choose between two regions in a state to install energy-producing wind turbines. A researcher claims that the wind speed in Region A is less than the wind speed in Region B. To test the regions, the average wind speed is calculated for 60 days in each region. The mean wind speed in Region A is 13.8 miles per hour. Assume the population standard deviation is 2.8 miles per hour. The mean wind speed in Region B is 15.1 miles per hour. Assume the population standard deviation is 3.1 miles per hour. At α = 0.05, can the company support the researcher's claim? Complete parts (a) through (d) below.(a) - \( C. \) The wind speed in Region A is not less than the wind speed in Region B.- \( \checkmark \) \( D. \) The wind speed in Region A is less than the wind speed in Region B.Let Region A be sample 1 and Region B be sample 2. Identify \( H_0 \) and \( H_a \).- \( H_0: \mu_1 \geq \mu_2 \)- \( H_a: \mu_1 < \mu_2 \)(b) Find the critical value(s) and identify the rejection region.The critical value(s) is/are \( z_0 = \) \(-1.645\). (Round to three decimal places as needed. Use a comma to separate answers as needed.)What is the rejection region? Select the correct choice below and fill in the answer box(es) within your choice. (Round to three decimal places as needed.)\( A. \, z > \) \( B. \, z < \) \(\square\) or \( z > \) \(\square\) \( \checkmark \) \( C. \, z < -1.645 \)(c) Find the standardized test statistic \( z \).\( z = \) \(\square\) (Round to two decimal places as needed.)

Given Information: Sample size = 60 Region A: Sample mean (x¯1) = 13.8 Population standard deviation (σ1) = 2.8 Region B: Sample mean (x¯2) = 15.1 Population standard deviation (σ2) = 3.1 Significance level α = 0.05 State the Hypothesis as follows: Null Hypothesis: H0:μ1≥μ2 Alternative Hypothesis: Ha:μ1<μ2 Calculation of the test statistic: Formula: z=x¯1-x¯2σ12n1+σ22n2 Substitute the values in the formula: z=13.8-15.12.8260+3.1260=-1.30.13067+0.16017≈-2.41 Thus, the value of the test statistic is -2.41 Critical value for a left tailed test at 0.05 significance level is -1.645 Since, computed value of the test statistic is less than the critical value, reject the null hypothesis and conclude that there is sufficient evidence to support the claim that the wind speed in region A is less than the wind speed in region B.