An empty steel container is filled with 0.0710 atm of HF. The system is allowed to reach equilibrium. If Kp = 2.76 for the reaction below, what is the equilibrium partial pressure of H₂? 2 HF (g) ⇌ H₂ (g) + F₂ (g)

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A: Given data, Initial pressure of HF = 0.0420atm Kp = 2.76

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A: For the given reaction, the equation for equilibrium pressure can be written as below,

Q: Kc

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A: Given data,Initial pressure of HF=0.0590atmKp of the reaction=2.76Given reaction;2HF(g)⇌H2(g)+F2(g)

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A: Interpretation - To determine the partial pressure of H2 for the reaction 2 HF (g) ⇌ H₂ (g) + F₂ (g)…

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A: Equilibrium partial pressure of HF = 1.206 atmExplanation:Step 1:

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Q: equilibrium partial pressure of B? Kp for this reaction is 67.2

A: For the given reaction, the equation for equilibrium pressure can be written as below,

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