An employee survey conducted two years ago by a company found that 46% of its employees were concerned about future health care benefits. A random sample of 84 of these employees were asked if they were now concerned about future health care benefits. Assuming that there has been no change in the level of concern about health care benefits compared to the survey two years ago, what is the upper limit of the sample proportion such that only 3% of the time the sample proportion would exceed this value?

An employee survey conducted two years ago by a company found that 46% of its employees were concerned about future health care benefits. A random sample of 84 of these employees were asked if they were now concerned about future health care benefits. Assuming that there has been no change in the level of concern about health care benefits compared to the survey two years ago, what is the upper limit of the sample proportion such that only 3% of the time the sample proportion would exceed this value?

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Jason collects information about annual family income from each student at his college. He computes both the mean and median family income across all students and is surprised to find that the mean income is much higher than the median income. What is the most likely reason for the difference in the mean and the median? Select one: a. The sample size is too small. b. The median tends to produce lower estimates of central tendency. c. The median is not an appropriate estimate for annual family income's level of measurement. Incorrect d. The mean is more affected by a small number of extreme values.
Because of the popularity of movies as an entertainment medium for college students, you plan to do a national study of the average cost of a movie ticket. If you assume that σ=$0.50, what sample size would you have to take to be 95% confident that your estimate was within $0.25 of the true mean ticket prices
One of the more popular statistics reported in the media is the president's job approval rating. The approval rating is reported as the proportion of the population who approve of the job that the sitting president is doing and is typically based on a random sample of registered voters. Complete parts (a) and (b) below. (This is a reading assessment question. Be certain of your answer because you only get one attempt on this question.) a) This proportion tends to fluctuate from week to week. Name some reasons for the fluctuation in the statistic. Select all valid reasons below. A. The proportion could be changing due to a large change in the composition of the population. B. The proportion could be changing due to sampling error; different people are in the sample. C. The proportion could be changing because the sampling size of the poll is changing. D. The proportion could be changing because people's attitudes are changing
A random sample of 300 physicians shows that there are 50 of them who make at least $200,000 a year. What is the test statistic if we want to test that the true proportion of physicians in the population who make at least $200,000 a year is less than 0.20?
A question in a poll taken in 2007 asked, "Do you think the penalties for underage drinking should be made more strict, less strict, or remain the same?" The sample proportion that responded "more strict" was 0.61 (61%). This result will be used to estimate the proportion of all adults in the United States who think that penalties for underage drinking should be more strict. The sample consisted of n = 500 randomly selected adults in the United States Calculate a 95% confidence interval that estimates the population proportion who think that penalties for underage drinking should be more strict. (Round your answers to three decimal places.)
A carnival game is designed so that approximately 10% of players will win a large prize. If there is evidence that the percentage differs significantly from this target, then adjustments will be made to the game. To investigate, a random sample of 100 players is selected from the large population of all players. Of these players, 19 win a large prize. The question of interest is whether the data provide convincing evidence that the true proportion of players who win this game differs from 0.10. Are the conditions for inference met for conducting a z-test for one proportion? Yes, the random, 10%, and large counts conditions are all met. No, the random condition is not met. No, the 10% condition is not met. No, the large counts condition is not met.
An amusement park keeps track of the percentage of individuals with season passes according to age category. An independent tourist company would like to show that this distribution of age category for individuals buying season passes is different from what the amusement park claims. The tourist company randomly sampled 200 individuals entering the park with a season pass and recorded the number of individuals within each age category. Age Category Child (under 13 years old) Teen (13 to 19 years old) Adult (20 to 55 years old) Senior (56 years old and over) Number of Individuals 56 86 44 14 The tourist company will use the data to test the amusement park’s claim, which is reflected in the following null hypothesis. H0:pchild=0.23H0:pchild=0.23, pteen=0.45pteen=0.45, padult=0.20padult=0.20, and psenior=0.12psenior=0.12. What inference procedure will the company use to investigate whether or not the distribution of age category for individuals with season passes is…
In 1995, the median price of a PC was $1200. Suppose that a random sample of100 persons who bought their PCs during that year recorded the amount spent (byeach of them) on his/her PC. State the approximate sampling distribution of ˆp, theproportion of persons who spent more than $1200 on a PC. Find the probabilitythat more than 60% of this group spent more than $1200. NOTE: Please explain each part, so the problem can be used as a Study Guide
A researcher studying public opinion of proposed Social Security changes obtains a simple random sample of 25 adult Americans and asks them whether or not support the proposed changes . To say that the distribution of the sample proportion of adults who respond yes, is approximately normal , how many more adult Americans does the researcher need to sample in the following cases? (a) 15% of all adult Americans support the changes (b) 20% of all adult Americans support the changes
The researcher is concerned that older persons may not be knowledgeable of the COFLU-20. As such, he is interested in investigating the association between the age of the respondents and their knowledge level. Table 2 below shows the knowledge level of respondents, by age group. Table 2 (image included) Conduct a test, at the 5% level of significance, to determine whether the data provided sufficient evidence to conclude that an association exists between age group and knowledge level. State the hypotheses to be tested: H0: H1: state the degrees of freedom for this test the p-value for this test, given that the chi-square test statistic, c2, is 11.029. state the conclusion for the test. Give reason for your answer.
Suppose the value of a stock varies each day from $10.82 to $23.17 with a uniform distribution. Find the third quartile, i.e. , 75% of all days the stock is below what value ?
A recent Gallup Poll interviewed a random sample of 1523 adults. Of these, 868 bought a lottery tickets in the past year. Suppose that in fact (unknown to Gallup) exactly 60% of all adults bought a lottery ticket in the past year. If Gallup took many simple random samples of 1,523 people, the sample proportion who bought a ticket would vary from sample to sample. The sampling distribution would be close to normal with a mean of 0.6 and a standard deviation of___ A)0.4899 B)0.0251 C)0.00016 D)0.0126