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An emergency patient can have two types of disease: Type I with probability 0.4 and Type Il with probability 0.6. If he does not receive adequate treatment, he could die with a probability of 0.8. The doctor can take three actions: 1. do not treat the patient 2. give the patient a drug 3. operate on the patient but these three actions are mutually exclusive. Both an operation and the drug can cause death to the patient, the first with probability 0.5 and the second with probability 0.2. If the patient survives the drug, it would have no effect with probability 0.5 if he had Type I disease, while the probability would be 1 if he had Type Il disease. In the event that he survives the operation, this would be beneficial with probability 0.8 if he has Type I disease and with probability 0.4 if he has Type II.

An emergency patient can have two types of disease: Type I with probability 0.4 and Type Il with probability 0.6. If he does not receive adequate treatment, he could die with a probability of 0.8. The doctor can take three actions: 1. do not treat the patient 2. give the patient a drug 3. operate on the patient but these three actions are mutually exclusive. Both an operation and the drug can cause death to the patient, the first with probability 0.5 and the second with probability 0.2. If the patient survives the drug, it would have no effect with probability 0.5 if he had Type I disease, while the probability would be 1 if he had Type Il disease. In the event that he survives the operation, this would be beneficial with probability 0.8 if he has Type I disease and with probability 0.4 if he has Type II.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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An emergency patient can have two types of disease: Type I with probability 0.4 and Type Il with probability 0.6. if he does not receive adequate treatment, he could die with a probability of 0.8. The doctor can take three actions: 1. do not treat the patient 2. give the patient a drug 3. operate on the patient but these three actions are mutually exclusive. Both an operation and the drug can cause death to the patient, the first with probability 0.5 and the second with probability 0.2. If the patient survives the drug, it would have no effect with probability 0.5 if he had Type I disease, while the probability would be 1 if he had Type Il disease. In the event that he survives the operation, this would be beneficial with probability 0.8 if he has Type I disease and with probability 0.4 if he has Type II. Draw a decision tree that allows you to follow the optimal strategy. What should the doctor do?
Transcribed Image Text:An emergency patient can have two types of disease: Type I with probability 0.4 and Type Il with probability 0.6. if he does not receive adequate treatment, he could die with a probability of 0.8. The doctor can take three actions: 1. do not treat the patient 2. give the patient a drug 3. operate on the patient but these three actions are mutually exclusive. Both an operation and the drug can cause death to the patient, the first with probability 0.5 and the second with probability 0.2. If the patient survives the drug, it would have no effect with probability 0.5 if he had Type I disease, while the probability would be 1 if he had Type Il disease. In the event that he survives the operation, this would be beneficial with probability 0.8 if he has Type I disease and with probability 0.4 if he has Type II. Draw a decision tree that allows you to follow the optimal strategy. What should the doctor do?
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