An emergency flooding system for a nuclear reactor core i reservoirs are actually at the similar heights. Assume a sha coefficients, the properties of water, and the equivalent ra could be found using the Moody chart. Find the power inp Pan 50,000 galons 750 ft of 3-in, schedule 160 stainless steel pipe lactual 1.D. is 2.625 in.1, three gate valves, seven 90 regular elbows W = Core *10³ hp

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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An emergency flooding system for a nuclear reactor core is shown in figure below. The pressure into the core is p₁ = 2200 psig. Both
reservoirs are actually at the similar heights. Assume a sharp-edged entrance, 60 °F water, and threaded connections. The loss
coefficients, the properties of water, and the equivalent roughness could be found using the tables in the textbook. The friction factor
could be found using the Moody chart. Find the power input required to flood the core at the rate of 5000 gal/min.
Pen
50,000
gallons
water
750 ft of 3-in. schedule 160 stainless
steel pipe (actual 1.D. is 2.625 in.1, three
gate valves, seven 90° regular elbows
W =
Core
*10 hp
Transcribed Image Text:An emergency flooding system for a nuclear reactor core is shown in figure below. The pressure into the core is p₁ = 2200 psig. Both reservoirs are actually at the similar heights. Assume a sharp-edged entrance, 60 °F water, and threaded connections. The loss coefficients, the properties of water, and the equivalent roughness could be found using the tables in the textbook. The friction factor could be found using the Moody chart. Find the power input required to flood the core at the rate of 5000 gal/min. Pen 50,000 gallons water 750 ft of 3-in. schedule 160 stainless steel pipe (actual 1.D. is 2.625 in.1, three gate valves, seven 90° regular elbows W = Core *10 hp
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