An elevator of mass 700 kg descends with an acceleration of 3 m/s^2 over a distance of 12 metres. What is the work done by the force of the earth's acceleration? -Elevator cable re Cab d
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A: Given data: a)Force F=130lb Distance d=1 ft b) Distance d=3 ft
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A: force = 14 lb stretch (d) = 4 in
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A: Draw the free-body diagram of the block as shown below.
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A: Required :: Work done, W
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A: Solution: Given Values, Mass(M)=50 Kgdistance(d)=0.240 mtime (t)=1 min=60 sec
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Q: 1. A crate of mass 10.0 kg is pulled up a rough 20 degrees incline. The pulling force is 100 N…
A: This is the FBD for the given system. Here, m = 10 kg θ = 200 F= 100 N µ = 0.4 d = 5 m
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A: We use the work-energy theorem to calculate the coefficient of friction.
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Q: A cable “lowers” a 3000 kg elevator at a constant velocity for a distance of 35.0 m What is the work…
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