An electron traveling from the sun as part of the solar windstrikes the earth’s magnetosphere at latitude 80.0° N in a region wherethe magnetic field has a strength of 15.0 mT and is directed toward theearth’s center. The electron has a speed of 400 km/s and is directed towardthe earth’s axis parallel to the equator. Magnetic forces send theelectron on a helical trajectory. What is the radius of this helix?

An electron traveling from the sun as part of the solar windstrikes the earth’s magnetosphere at latitude 80.0° N in a region wherethe magnetic field has a strength of 15.0 mT and is directed toward theearth’s center. The electron has a speed of 400 km/s and is directed towardthe earth’s axis parallel to the equator. Magnetic forces send theelectron on a helical trajectory. What is the radius of this helix?

Similar questions

An electric charge q1 moving with the velocity v1 produces a magnetic field B given by В Orl 47 r2 where î points from q1 to the point at which B is measured (Biot-Savart law, (a) Show that the magnetic force F12 on a second charge q2, velocity v2 due to the first one, is given by the triple product lo 9192 F12= 47 r2 Üz × (01 × î).
An electron traveling from the sun as part of the solar windstrikes the earth’s magnetosphere at latitude 80.0° N in a region wherethe magnetic field has a strength of 15.0 mT and is directed toward theearth’s center. The electron has a speed of 400 km/s and is directed towardthe earth’s axis parallel to the equator. Magnetic forces send theelectron on a helical trajectory. This electron strikes the ionosphere, where it is furtheraccelerated by an electric field with strength 20.0 mV/m directednorthward parallel to the earth’s surface. What is the electron’s newspeed after it has been deflected 100 km southward by this field?
a strong magnet is placed under a horizantal conducting ring of radius r that carries current I as shown in the figure. If the magnetic field B makes an angle teta with the vertical at the ring's location, what are the magnitude and the direction of the resultant magnetic force on the ring?
A cyclotron is a device for accelerating charged particles to high speed as they follow an expanding spiral-like path (See LHC, NSRRC, or an MRI machine). The charged particles are subjected to both an electric field and a magnetic field. One of these fields increases the speed of the charged particles, and the other field causes them to follow a curved path. Which one does the latter? The magnetic field, since it exerts a force to the moving charge perpendicular to the charges' direction of motion. The electric field, since it exerts a force that accelerates the particle in the curved path of the facility. Not necessarily only one. Both contributes to the particles' curving of path as both exert force perpendicular to their velocity's direction. None of them. The curving of charges occur due to the design of the facility/device.
A particle with charge 8.11 x 10^-6 C moves at 4.75 x 10^6 m/s through a magnetic field of strength 4.14 T. The angle between the particle s velocity and the magnetic field direction is 55.1 degrees and the particle undergoes an acceleration of 7.7 m/s^2. What is the particle s mass? 9.2 kg 16.99 kg 3.9 kg 5.4 kg
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An electron traveling from the sun as part of the solar windstrikes the earth’s magnetosphere at latitude 80.0° N in a region wherethe magnetic field has a strength of 15.0 mT and is directed toward theearth’s center. The electron has a speed of 400 km/s and is directed towardthe earth’s axis parallel to the equator. Magnetic forces send theelectron on a helical trajectory. What is the frequency of the motion?
Q. 2: The velocity of an electron at an instant moving in a magnetic field B = (3.0 î + 4.0ĵ)mT is given by v = (300 î – 400ĵ)km/s. Calculate the magnetic force acting on the electron. What is the radius of the electron orbit?
A particle with charge q enters a region with a uniform magnetic field Bthat acts in x and z directions (By = 0). The initial velocity of the particle is v = 2î +3ŷ. The force acting on the particle is given by F = q(-3 î + 2ĵ – 9k). Find the magnetic field vector B O a. B= -3î – k O b. B = 3î . O c. B= 2î + 3k O d. B= 4î – 2k O e. B= 2î – 3k