An electron traveling due north enters a region that contains a uniform magnetic field that points due east. In which direction will the electron be deflected?
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A: Given, v = 1.07 * 106 m/s B = 0.282 T we know, ( m*v2 ) / r = q*B*v r = m*V / q*B where, q…
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- Suppose that the dipole moment associated with an iron atom of an iron bar is 2.8 x 1023 J/T. The bar is 5.2 cm long and has a cross-sectional area of 1.5 cm2. Two-thirds of the atoms have their dipole moment in one directions and remaining one-third have their dipole moment in the opposite direction. What torque (in N*m) must be exerted to hold this magnet perpendicular to an external field of 1.2 T? (The density of iron is 7.9 g/cm3 and its molar mass is 55.9 g/mol. Avogadro's number is 6.022*1023 atoms/mol.)A particle of charge 18 µC feels a force of 2.4 × 10−4 N when it moves at a speed of 24 m/s in a direction perpendicular to a magnetic field. (a) What is the strength of the magnetic field in this region? (b) What is the force on the particle when it moves with a speed of 6.3 m/s at an angle of 25o relative to the direction of the magnetic field?An electron traveling from the sun as part of the solar windstrikes the earth’s magnetosphere at latitude 80.0° N in a region wherethe magnetic field has a strength of 15.0 mT and is directed toward theearth’s center. The electron has a speed of 400 km/s and is directed towardthe earth’s axis parallel to the equator. Magnetic forces send theelectron on a helical trajectory. This electron strikes the ionosphere, where it is furtheraccelerated by an electric field with strength 20.0 mV/m directednorthward parallel to the earth’s surface. What is the electron’s newspeed after it has been deflected 100 km southward by this field?
- If the potential difference over a length of copper wire is 1.5 V, how long must the copper wire be so that when placed in the magnetic field of the Earth at the equator, the copper wire will levitate? In which direction (North, South, East, or West) must the current flow in the wire in order to pull off this trick? Can this be done at the North or South Pole?A uniform magnetic field points vertically upward; its magnitude is 0.520 T. An electron with kinetic energy 6.50 × 10−18 J is moving horizontally eastward in this field. What is the magnetic force acting on it? Answer in units of "N north"A long, straight wire carries a current. There is a uniform magnetic field directed downward (not due to the wire) and the force exerted on the wire is directed to the left. In what direction is the current?
- A proton moves in a circular motion perpendicular to a uniform magnetic field of 0.75 T. Find the time for the proton to make one complete circular orbit.A proton that has a speed equal to 9.00105 m/s enters a region with a uniform magnetic field that has a magnitude of 0.730T and points into the page, as shown in the figure below. The proton enters the region at an angle θ= 60°. Find the exit angle φ and the distanced d.At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 8.39 ✕ 105 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength (B) is 1.37 ✕ 10−4 T? (Hint: First calculate the radius of circular path of an electron and use it to calculate the speed of proton) me=9.109*10-31, mp=1.67*10-27, q=1.602*10-19