Answered: An electron that has a velocity with x… | bartleby

Related questions

Question

An electron that has a velocity with x component 1.8 x 106 m/s and y component 4.2 × 106 m/s moves
through a uniform magnetic field with x component 0.025T and y component -0.18 T. (a) Find the
magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the
same velocity.
(a) Number i
(b) Number i
Units
Units

Expert Solution

Step by step

Solved in 3 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

An electron is introduced into a uniform magnetic field, Bx = 50.0 μTesla directed at right angles to the electron’s velocity vy = 5 x105 m/s. The electron subsequently moves in a circular path. What is the radius of the circular path?
(a) At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 7.25 x 106 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.05 × 10-5 T? m/s (b) What would the radius (in m) of the path be if the proton had the same speed as the electron? (c) What would the radius (in m) be if the proton had the same kinetic energy as the electron? (d) What would the radius (in m) be if the proton had the same momentum as the electron?
An electron moves in a circular path with a speed of 1.22 x 10' m/s in the presence of a uniform magnetic field with a magnitude of 2.12 mT. The electron's path is perpendicular to the field. (a) What is the radius (in cm) of the circular path? cm (b) How long (in s) does it take the electron to complete one revolution? S
A proton with kinetic energy 2.1 MeV enters perpendicular to a region of 0.33 T magnetic field that is pointing out of page. (a) What is the magnitude and direction of the magnetic force experienced by the charge? (b) What is the path of the proton within the magnetic field? B +,
An electron that has a velocity with x component 2.2 × 106 m/s and y component 3.2 × 106 m/s moves through a uniform magnetic field with x component 0.039 T and y component -0.19 T. (a) Find the magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the same velocity.
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.240 T. If the kinetic energy of the electron is 4.10 x 10-19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron m/s (b) the radius of the circular path μm
An electron moves in a circular path with a speed of 1.49 x 10' m/s in the presence of a uniform magnetic field with a magnitude of 1.88 mT. The electron's path is perpendicular to the field. (a) What is the radius (in cm) of the circular path? cm (b) How long (in s) does it take the electron to complete one revolution? S
-27 kg is The charge of an electron and a proton are both equal to q = 1.602 x 10-19 but the mass of a proton mp = 1.673 x 10 much larger than the mass of an electron me = 9.11 x 10-31 kg. If a proton and an electron move at the same speed in a circular path in a uniform magnetic field, what is the ratio of the radius of the proton's circular path r, to the radius of the electron's circular path Image size: s ML Max re. In other words what is rp/re? Note: the picture of the circular paths for the electron and proton are not drawn to scale. メ re Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g. 0.23, -2, 1e6, 5.23e-8
An electron moves in a circular path with a speed of 1.36 x 107 m/s in the presence of a uniform magnetic field with a magnitude of 1.84 mT. The electron's path is perpendicular to the field. (a) What is the radius (in cm) of the circular path? cm (b) How long (in s) does it take the electron to complete one revolution? S Read It