An Electron (qe= 1.6 x 1019c & me= 9.1 x 103-kg) is moving in a circular orbit of radius 50cm in a uniform magnetic field of 6 Tesla perpendicular to the velocity of the proton. • Find the speed of the electron. • Find its angular speed. Find Periodic Time of the motion. • Find applied Electric Field.

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A: Given  I1 = 3.15 A I2 = 5.20 A

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A: Magnitude of the charge                                         q = - 4.6 μC Speed of the charge…

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Q: •8 In Fig 29-40, two semicircular arcs have radii R = 7.80 cm and R = 3.15 cm, carry current i 0.281…

A: Given : Radius, R1 = 3.15 cm = 0.0315 m Radius, R2 = 7.80 cm = 0.078 m Current through the arcs, I =…

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A: force acting on a charge particle in magnetic field  F = qvB Sinθ

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A: Given Data: Charge on the particle is q = 5 µC. Velocity of the particle is v = 6 x 106 m/s.…

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A: Given Magnetic field 0.639 TRadius 713 mVelocity 169 m/sTo find out Mass of particle

Q: q=91 µC

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Q: [1×10-" C] A particle with a charge and a 3.1x10 " kg m's follows a circular path in a plane…

A: Given data:  Charge (q) = 1×10-12 C Momentum (P) = mv = 3.1×10-15 kg.m/s Magnetic field (B) = 2.5 T…

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A: Given :m=6.40×10-27KgVoltage =0.5VMagnetic force B=0.01 Teslax=4cm

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Q: Shown in the figure below is an experiment with an electron (9 - -1.602e-19 Coulombs, m - 9.109e-31…

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A: Given B= 6.79 mT = 6.79×10-3 T Speed v = 7.71×107 m/s

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A: F = qE i + qVB k  F = -1.6×10-19(1.6×104i + 1.10 × 107×0.005k)  F = -2.56×10-15 i - 8.8×10-15 k

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