AN ELECTRON MOVING 8 X 10^3m/s IN A 3.75 T MAGNETIC FIELD EXPERIENCES A MAGNETIC FORCE OF 2.5 X10^-13 N. WHAT ANGLE DOES THE VELOCITY OF THE ELECTRON MAKE WITH THE ELECTRIC FIELD ?
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A: Answer:- Given Velocity of electron (V) = 4.00 × 103 m/s Magnetic field (B) = 1.25 T Magnetic…
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A: Given Data Uniform magnetic field is given as B→=(30.0 i^-20.0j^) mT=(30.0i^-20.0j^ )×10-3 T…
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Q: An electron moving at 4.00 X 103 m/s in a 1.25-T magnetic field experiences a magnetic force of 1.40…
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Q: An electron moving at 4.00x10-m/s in a 1.25-T magnetic field experiences a magnetic force of 8.0…
A: Answer:- Given Velocity (V) = 4.00 × 103 m/s Magnetic field (B) = 1.25 T Magnetic force (F) =…
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Q: Please refer again to the diagram. This time we have a charge of 5.52 x 10^-6 C moving at velocity…
A: Given data: Charge (q) = 5.52×10-6 CVelocity (v) = 5.73×105 m/sMagnetic field (B) = 1.53 TElectric…
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Q: An electron moving at 3.70 x 103 m/s in a 1.25 T magnetic field experiences a magnetic force of 1.40…
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A: Charge (q) = 5.47 C Speed (v) = 6.98 m/s Magnetic field (B) = 6.28 T
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A: The formula for the force is,
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Q: given by v = (300 î + 400ĵ)km/s. Calculate the magnetic force acting on the electron. Q. 2: The…
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A: The relation for the force on a particle moving in a magnetic field is given by, F=qV×B --------(1)…
Q: An electron moving at 3.90 ✕ 103 m/s in a 1.20 T magnetic field experiences a magnetic force of 1.40…
A: Velocity of electron (v) = 3.90 ✕ 103 m/s Magnetic field (B) = 1.20 TForce(F) = 1.40 ✕ 10−16 N
Q: See the attached figure for this problem. There is a charge of 6.24 x 10^-6 C moving at velocity…
A: Calculate the magnetic field due to the charge. Fm=qvBFm=(6.24×10−6 C)(8.62×105 m/s)(3 T)Fm=16.1 N
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A: Given data is, q=4.8×10-19 Cm=7.95×10-26 Kgθ=900B=1.15 TR=33.5 cm=0.335 mV=Velocity=?
Q: Please refer again to the diagram. This time we have a charge of 2.58 x 10^-6 C moving at velocity…
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A: Given data: Charge to mass ratio of ion, qm=1.10×104 C/kg Magnetic field, B=9×10-1 T=0.9 T Radius…
Q: Here the charge is 3.09 x 10^-6 C, the magnetic field strength is 1.03 T and the electric field…
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A: Given that charge q=0.9 C magnetic field B=0.4T velocity v=700 m/s angle=90 deg.
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Q: Here we have a charge of 2.58 x 10^-6 C moving at velocity 5.36 x 10^5 m/s through a magnetic field…
A: Given data-Charge q= 2.58 x 10^-6 C Velocity v = 5.36 x 10^5 m/sMagnetic field B = 4.82 TElectric…
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A: Given Part-A strength of magnetic field = B = 2.0 mT. speed of electron = v = 7.1 x 106 m/s . angle…
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A: Given, Speed , v = 3.2×105 m/s uniform magnetic field , B = 8.0 mT =8×10-3T into the page. charge ,…
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Q: A charged particle with speed v = 3.5 x 10° m/s enters a uniform magnetic field of B = 1.4 T. The…
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AN ELECTRON MOVING 8 X 10^3m/s IN A 3.75 T MAGNETIC FIELD EXPERIENCES A MAGNETIC FORCE OF 2.5 X10^-13 N. WHAT ANGLE DOES THE VELOCITY OF THE ELECTRON MAKE WITH THE ELECTRIC FIELD ? THERE ARE TWO ANSWERS
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