An electron moves horizontally across the Earth's equator at a speed of 2.50 × 10° m/s and in a direction 35.0° N of E. At this point, the Earth's magnetic field has a direction due north, is parallel to the surface, and has a value of 3.00 x 10 T. What is the force acting on the electron due to its interaction with the Earth's magnetic field? O 6.88 x 10-18 N due west O 6.88 x 10 18 N toward the Earth's surface O 9.83 x 10-18 N toward the Earth's surface O 9.83 x 10-18 N away from the Earth's surface O 4.00 x 10-18 N away from the Earth's surface
An electron moves horizontally across the Earth's equator at a speed of 2.50 × 10° m/s and in a direction 35.0° N of E. At this point, the Earth's magnetic field has a direction due north, is parallel to the surface, and has a value of 3.00 x 10 T. What is the force acting on the electron due to its interaction with the Earth's magnetic field? O 6.88 x 10-18 N due west O 6.88 x 10 18 N toward the Earth's surface O 9.83 x 10-18 N toward the Earth's surface O 9.83 x 10-18 N away from the Earth's surface O 4.00 x 10-18 N away from the Earth's surface
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter19: Magnetism
Section: Chapter Questions
Problem 8P: An oxygen ion (O+) moves in the xy-plane with a speed of 2.50 103 m/s. If a constant magnetic field...
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