An electron moves at 2.40 x 10 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.10 x 10-2 T. Part A What is the largest possible magnitude of the acceleration of the electron due to the magnetic field? Express your answer with the appropriate units. undo rego Teset keyboard shortcuts Help m a = 3.33 • 1016 Submit Prevlous Answers Request Anawer X Incorrect; Try Again; 5 attempts remaining Part B What is the smallest possible magnitude of the acceleration of the electron due to the magnetic field? Express your answer with the appropriate units. a = 0 Previous Anewere v Correct Part C If the actual acceleration of the electron is one-fourth of the largest magnitude in part A, what is the angle between th Express your answer in degrees to three significant figures. O= 14.5

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An electron moves at 2.40 x 10 m/s through a region in which there is a magnetic field of
unspecified direction and magnitude 7.10 x 10-2 T.
Part A
What is the largest possible magnitude of the acceleration of the electron due to the magnetic field?
Express your answer with the appropriate units.
undo rego Tese keyboard shortcuts Help
m
a = 3.33 • 1016
Submit
Prevlous Anewers Request Answer
X Incorrect; Try Again; 5 attempts remaining
Part B
What is the smallest possible magnitude of the acceleration of the electron due to the magnetic field?
Express your answer with the appropriate units.
a = 0
Prevlous Anewere
v Correct
Part C
If the actual acoeleration of the electron is one-fourth of the largest magnitude in part A, what is the angle between th
Express your answer in degrees to three significant figures.
0= 14.59
Previoua Anaware
O Type here to search
99+
Transcribed Image Text:An electron moves at 2.40 x 10 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.10 x 10-2 T. Part A What is the largest possible magnitude of the acceleration of the electron due to the magnetic field? Express your answer with the appropriate units. undo rego Tese keyboard shortcuts Help m a = 3.33 • 1016 Submit Prevlous Anewers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B What is the smallest possible magnitude of the acceleration of the electron due to the magnetic field? Express your answer with the appropriate units. a = 0 Prevlous Anewere v Correct Part C If the actual acoeleration of the electron is one-fourth of the largest magnitude in part A, what is the angle between th Express your answer in degrees to three significant figures. 0= 14.59 Previoua Anaware O Type here to search 99+
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