an electron (m = 9.11x10-31 kg) accelerates in a uniform electric field E = 1.45 x 104 N/C. What is the acceleration of theelectron after it traveled 10 cm in the electric field?O A.2.55 x 1014 m/s2B.1.5 x 1014 m/s?O C. 1.5 x 1015 m/s2O D. NoneO E. 2.55 x 1015 m/s?

Given Charge is q=1.60×10^-19 C Mass of an electron is m=9.11×10^-31 kg Electric field is…

an electron (m = 9.11x10-31 kg) accelerates in a uniform electric field E = 1.45 x 104 N/C. What is the acceleration of th electron after it traveled 10 cm in the electric field? O A. 2.55 x 1014 m/s2 В. 1.5 x 1014 m/s? ос. 1.5 х 1015 m/s? O D. None O E. 2.55 x 1015 m/s?

an electron (m = 9.11x10-31 kg) accelerates in a uniform electric field E = 1.45 x 104 N/C. What is the acceleration of th electron after it traveled 10 cm in the electric field? O A. 2.55 x 1014 m/s2 В. 1.5 x 1014 m/s? ос. 1.5 х 1015 m/s? O D. None O E. 2.55 x 1015 m/s?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Find the magnitude and direction of the electric field acting at the coordinate, x = 15 cm, in the…

A: Given data: Charge (q1) = +8.00 pC at x = 6.0 cm Charge (q2) = +5.00 pC at x = 12 cm k = 9.00×109…

Q: An electron is accelerated by a constant electric field of magnitude 330 N/C. (a) Find the…

A: (a) The acceleration of the electron is 58.022 X 1012 m/sec2 (b) The electron's speed is 4.932 X…

Q: a) A uniform electric field has a magnitude of 2.3 x10³ In a vacuum, a proton begins with a speed of…

Q: A proton and an electron are moving due east in a constant electric field that also points due east.…

A: Given that, Electric field, E=2.0×104 N/C (due east) Mass of the proton, mp=1.67×10-27 kg Mass of…

Q: An proton is released from rest in a uniform electric field and accelerates to the east at a rate of…

Q: Part 1: An electron is accelerated by a constant electric field of magnitude 318 N/C. Find the…

Q: 22. A doubly charged ion is accelerated to an energy of 32.0 keV by the electric field between two…

A: Write the expression for the energy and substitute the required values to determine the potential…

Q: An electron is accelerated by a constant electric field of magnitude 285 N/C. (a) Find the…

A: (a) According to the Newton's second law of motion, the force acting on the object is, F=ma The…

Q: A proton and an electron are moving due east in a constant electric field that also points due east.…

A: Magnitude of electric field, E= 7.0 x 104 N/C

Q: An electron is placed in a vertical electric field. The electron experiences a downward acceleration…

A: Given data: Magnitude of downward acceleration of electron is, a=4.0 m/s2.

Q: Find the electric field ( in units of N/C) needed to accelerate a charged particle (m=22 µg and q=33…

A: Initial speed = u = 0 m/s ( rest) Final speed = v = 100 m/s Distance travelled s = 592.6 cm = 592.6…

Q: A proton and an electron are moving due east in a constant electric field that also points due east.…

A: The electron and proton has same charge, hence the net force acting on the electron and proton is…

Q: If an electron experiences a constant acceleration of 2.0x1014m/s2 in a uniform electric field.…

A: Given data The accleration is a=2.0×1014 m/s2 The charge is qe=-1.60×10-19 C The mass of the…

Q: A proton is initially at rest. After some time, a uniform electric field is turned on and the proton…

Q: An electron with speed 2.15×107 m/sm/s is traveling parallel to a uniform electric field of…

A: Ignoring relativistic effects we can solve the above question in the following method:-

Q: Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a…

Q: What is the magnitude and direction of the electric field?

A: The force on a proton is given as F = qE.... Where E is electric field and its direction is same as…

Q: An electron (m = 9.11 x 10-31 kg) in empty space experiences an upward electric force equal to 25…

A: The given data are listed below with suitable variables. Here, m denotes the electron’s mass, F…

Q: A particle (mass = 4.0 g, charge = 51 mC) moves along the x-axis in a region of space where the…

A: Data given , Mass of the particle ( m ) = 4 gm = 4 × 10-3 kg…

Q: Any electron with a speed v0= 5.26x10^6 m/s is traveling paratroopers an electric field of magnitude…

Q: An electron is accelerated by a constant electric field of magnitude 295 N/C. (a) Find the…

A: Given:- The magnitude of the constant electric field is E = 295 N/C. An electron is accelerated in…

Q: Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a…

A: Force exerted on electron in cathode ray tube is electric field. Formula of electric field is as…

Q: An electron is traveling through a region of space in which the electric fiels is along the +x…

Q: The electron gun in a television tube accelerates electrons (mass = 9.11 x 10-31 kg, charge = 1.60 ×…

A: Calculate the acceleration of electrons using equation of kinematics,

Q: An electron has an initial velocity of 6.00 ✕ 106 m/s in a uniform 9.00 ✕ 105 N/C strength electric…

A: Given data: The initial velocity, v=6.00×106 m/s The electric field E= 9.00×105 N/C

Q: An electron is released from rest in a uniform electric field. The electron accelerates vertically…

Q: Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a…

A: Given data The magnitude of the electric field is given as E = 315 N/C. The time interval is given…

Q: An electron is moving with a velocity, v = ( 0.000i, 6.95x10³j, 0.00k)m/s, when it enter a region of…

A: a. as we know that the force acting on the electron and electric field are related as: F =qE ma = qE…

Q: An electron is released from rest in a uniform electric field. The electron accelerates vertically…

A: Given that:u=0 m/ss=4.5 mt=3 ms

Q: Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a…

A: (a) Acceleration, a = Force / Mass of electron Force of an electron, F = eE Thus, a = eE / m a =…

Q: An electron is released from rest in a uniform electric field of magnitude 3.51 ✕ 104 N/C. Calculate…

A: Let m be the mass of the electron, q be the charge on electron, E be the electric field, a be the…

Q: An electron is placed in a uniform electric field of E = (3.24 x 10e3 N/C) i + (1.35 x 10e3 N/C) j .…

Q: simple and common technique for accelerating electrons is shown in the figure below, where there is…

A: Solution: Given: m = mass of electron = 9.11 x 10-31 kg e = charge on electron = -1.60 x 10-19 C E =…

Q: (a) What is the magnitude of the acceleration of the electron (in m/s2)? m/s2 (b) The electron is…

A: Given data The magnitude of electric filed is, E=290 N/C The time is t=9.00×10-9 s (a) The magnitude…

Q: An electron is accelerated by a constant electric field of magnitude 295 N/C. (a) Find the…

A: (a)Electric field of an electron,(E)=(-)295 N/C -----(1) [Given] [Negative sign just indicates the…

Q: Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a…

Q: ng from rest, are accelerated by the same uniform electric field of 260N/C. Determine the distance…

A: For the electron We know that the electrostatic force in terms of the electric field is given as F…

Q: Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of…

A: Given: The magnitude of the electric field is E=275 N/C,

Q: What is the magnitude of the acceleration of the electron (in m/s²)? 4.0✔ m/s² The electron is…

Q: A proton is placed in an electric field of intensity 770 N/C. What are the magnitude of the…

A: Given: The strength of the electric field is 770 N/C. The mass of the proton is 1.67x10-27 kg. The…

Q: An electron is accelerated eastward at 2.28 × 109 m/s2 by an electric field. Determine the magnitude…

Q: Inside a radiation therapy device, an electron is in the presence of a uniform electric field with a…

A: Given that:- Strength of uniform Electric field=295N/C

Q: An electron is accelerated by a constant electric field of magnitude 270 N/C. (a) Find the…

A: Given Data: Electric field = E = 270 N/C Charge of an electron = e = 1.6 x 10-19 C Mass of an…

Q: An electron is traveling through a uniform electric field. The field is constant and given by…

A: An electron is moving through uniform electric field Electric field is E→=2×10-11 N/Ci^-1.20×10-11…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

an electron (m = 9.11x10-31 kg) accelerates in a uniform electric field E = 1.45 x 104 N/C. What is the acceleration of the
electron after it traveled 10 cm in the electric field?
O A.
2.55 x 1014 m/s2
B.
1.5 x 1014 m/s?
O C. 1.5 x 1015 m/s2
O D. None
O E. 2.55 x 1015 m/s?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

An electron is moving horizontally at 3 x 10^6 m/s when it enters an electric field. If the electron deflects 0.9 cm downward in a distance of 2.5 cm determine the magnitude and direction of the electric field.
Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a magnitude of 275 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s2)? m/s2 (b) The electron is initially at rest. What is its speed (in m/s) after 1.20 ✕ 10−8 s? m/s
Question 8 of 22 In the figure, g = 1.00 x 10-7 C and q, = 8.00 x 10-7 C. x(cm) 3 5 8. 6. What is the magnitude E of the electric field at the point (x, y) = (0.00 cm, 3.00 cm)? E = N/C What is the angle 0g that the direction of the electric field makes at that position, measuring counterclockwise from the Og = positive x-axis? What is the magnitude F of the force acting on an electron at that position? F = What is the angle 0p of the force acting on an electron at that position, measuring counterclockwise from the positive x- Or = axis?
An electron is released from rest in a uniform electric field. If the electric field is 1.25 kN/C, at the end of 20 ns the electron's velocity will be approximately Group of answer choices 3.9 × 103 m/s. 4.4 × 106 m/s. 2.5 × 103 m/s. 3.0 × 108 m/s. 2.5 × 10–5 m/s.
A proton is initially at rest. After some time, a uniform electric field is turned on and the proton accelerates. The magnitude of the electric field is 1.46 105 N/C. What is the speed of the proton after it has traveled 7.00 cm? What is the speed of the proton after it has traveled 70.0 cm?
An electron, initially at rest is placed in an electric field of 5?105 ?∕? directed west. What is the acceleration of the electron due to the electric field? Group of answer choices 4.79x10^13 m⁄s^2 4.79x10^-13 m⁄s^2 8.78x10^-16 m⁄s^2 8.78x10^16 m⁄s^2
At some instant the velocity components of an electron moving between two charged parallel plates are vx=1.6×105 m/s and vy-3.4x10³ m/s. Suppose the electric field between the plates is uniform and given by E what are (a) the electron's acceleration in that field and (b) the electron's velocity when its x coordinate has changed by 2.1 cm? 120N/C). In unit-vector notation, (a)(i (b)(i ~)J. ✓ )it( i THIN OF
The electron gun in a 1990’s style television tube uses a uniform electric field to accelerate electrons from rest to 5.0 × 107 m/s in a distance of 1.2 cm. What is the electric field strength?
A proton and an electron are moving due east in a constant electric field that also points due east. The electric field has a magnitude of 2.0 × 104 N/C. Determine the magnitude of the acceleration of the proton and the electron.
A proton and an electron are moving due east in a constant electric field that also points due east. The electric field has a magnitude of 6.0 × 104 N/C. Determine the magnitude of the acceleration of the proton and the electron. ар ae =
Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of 310 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s²)? 5.14e13 X How is the electric force related to the electric field? How is the acceleration related to the force? What m/s² -9 (b) The electron is initially at rest. What is its speed (in m/s) after 8.50 x 10 s? m/s
A proton is fired horizontally into a 1.0×105N/C vertical electric field. It rises 1.0 cm vertically after having traveled 6.0 cm horizontally. What was the proton's initial speed?