An electron is initially at rest at distance 0.15 m from a fixed charge Q = -5.00×10-9 C. The electron accelerates. How fast is it moving when the distance is 0.3 m?
An electron is initially at rest at distance 0.15 m from a fixed charge Q = -5.00×10-9 C. The electron accelerates. How fast is it moving when the distance is 0.3 m?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![**Problem Statement:**
An electron is initially at rest at a distance of 0.15 m from a fixed charge \( Q = -5.00 \times 10^{-9} \) C. The electron accelerates. How fast is it moving when the distance is 0.3 m?
---
**Explanation:**
To solve this problem, you'll need to use principles of electrostatic force and energy conservation. Here’s a step-by-step guide:
1. **Coulomb’s Law:** Calculate the electrostatic force between the charge \( Q \) and the electron at the initial and final positions.
2. **Electric Potential Energy:** Determine the initial and final electric potential energy of the electron by the formula:
\[
U = \frac{k \cdot Q \cdot q}{r}
\]
where:
- \( k \) is Coulomb's constant (\( 8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2 \)),
- \( q \) is the charge of the electron (\(-1.60 \times 10^{-19} \, \text{C}\)),
- \( r \) is the distance from the charge.
3. **Conservation of Energy:** Apply the conservation of energy principle. The loss in electric potential energy converts into kinetic energy of the electron:
\[
\Delta U = - \Delta K
\]
4. **Kinetic Energy:** Calculate the change in kinetic energy to find the speed \( v \) of the electron:
\[
K = \frac{1}{2} mv^2
\]
where \( m \) is the mass of the electron (\(9.11 \times 10^{-31} \, \text{kg}\)).
5. **Equation Solving:** Solve for \( v \) using the conservation equation:
\[
\Delta U = \frac{1}{2} mv^2
\]
This solution approach combines physics concepts to find out how fast the electron is moving at a new distance.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F007d2f28-0b15-4cef-98f8-cbb273656312%2Fd2a40d90-fcb4-4e76-9111-917e305a7abd%2F9igm6j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
An electron is initially at rest at a distance of 0.15 m from a fixed charge \( Q = -5.00 \times 10^{-9} \) C. The electron accelerates. How fast is it moving when the distance is 0.3 m?
---
**Explanation:**
To solve this problem, you'll need to use principles of electrostatic force and energy conservation. Here’s a step-by-step guide:
1. **Coulomb’s Law:** Calculate the electrostatic force between the charge \( Q \) and the electron at the initial and final positions.
2. **Electric Potential Energy:** Determine the initial and final electric potential energy of the electron by the formula:
\[
U = \frac{k \cdot Q \cdot q}{r}
\]
where:
- \( k \) is Coulomb's constant (\( 8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2 \)),
- \( q \) is the charge of the electron (\(-1.60 \times 10^{-19} \, \text{C}\)),
- \( r \) is the distance from the charge.
3. **Conservation of Energy:** Apply the conservation of energy principle. The loss in electric potential energy converts into kinetic energy of the electron:
\[
\Delta U = - \Delta K
\]
4. **Kinetic Energy:** Calculate the change in kinetic energy to find the speed \( v \) of the electron:
\[
K = \frac{1}{2} mv^2
\]
where \( m \) is the mass of the electron (\(9.11 \times 10^{-31} \, \text{kg}\)).
5. **Equation Solving:** Solve for \( v \) using the conservation equation:
\[
\Delta U = \frac{1}{2} mv^2
\]
This solution approach combines physics concepts to find out how fast the electron is moving at a new distance.
Expert Solution
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Step 1: Change in potential and kinetic energy
The initial potential energy will be converted into kinetic energy:
Where,
is initial potential energy,
is final potential energy,
is initial kinetic energy,
is final potential energy,
Step by step
Solved in 3 steps with 9 images
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